Ask question

Ask question

All categories

3 years ago

5

A seasonal index for a monthly series is about to be calculated on the basis of three years’ accumulation of data. The three pre

vious July values were 110, 150, and 130. The average over all months is 190. The approximate seasonal index for July is:

1 answer:

yarga [219]3 years ago

6 0

Answer:

0.684

Step-by-step explanation:

According to the scenario, computation of the given data are as follows

Seasonal index = Average value for July ÷ Average over all months

Where, Average value for July = ( 110 + 150 + 130 ) ÷ 3

= 390 ÷ 3 = 130

And, average over all months = 190

So by putting the value in the formula, we get

Seasonal index = 130 ÷ 190

= 0.684211 or 0.684

Hence, approximate seasonal index for July is 0.684.

You might be interested in

What is the answer to question 41

Nina [5.8K]

Answer:

an = 6 +5(n-1)

an = 1 +5n

Step-by-step explanation:

The equation for an arithmetic term is

an =a1 +d(n-1)

where a1 is the 1st term and d is the common difference

an = 6 +5(n-1)

We can distribute the 5

an = 6+5n-5

an = 1 +5n

4 0

3 years ago

Kim's age is twice that of her sister. When you add Kim's age to her sister's age, you get 42. How old is each sister?

xz_007 [3.2K]

Answer:

a: K = 2s

K + s = 42

b: 2s + s = 42

K = 28

s = 14

Step-by-step explanation:

1. Come up with equations based on the information given.

K = Kim

s = sister

Kim is twice of her sister -> K = 2s

When you add Kim's age to her sister's age, you get 42 -> K + s = 42

2. Substitue for K to find out the value of s

K = 2s

2s + s = 42

3. Solve for s

s = 42/3

s= 14

4. Solve for K

K = 2s

K = 2*14

K = 28

7 0

3 years ago

Dominic owns a small business selling used books. He knows that in the last week

Sav [38]

Answer:

About 9% or 0.09

Step-by-step explanation:

3 0

3 years ago

Convert,the complex number into polar form: 4+4i

kow [346]

Z = a + bi
z = 4 + 4i

r² = a² + b²
r² = (4)² + (4)²
r² = 16 + 16
r² = 32
r = 4√(2)
r = 4(1.414)
r = 5.656

$cos\theta = \frac{a}{r}$
$cos\theta = \frac{4}{4\sqrt{2}}$
$cos\theta = \frac{4}{4\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}}$
$cos\theta = \frac{4\sqrt{2}}{4\sqrt{4}}$
$cos\theta = \frac{4\sqrt{2}}{4(2)}$
$cos\theta = \frac{4\sqrt{2}}{8}$
$cos\theta = \frac{\sqrt{2}}{2}$
$2(cos\theta) = 2(\frac{\sqrt{2}}{2})$
$2cos\theta = \sqrt{2}$
$2cos\theta = 1.414$

$sin\theta = \frac{b}{r}$
$sin\theta = \frac{4}{4\sqrt{2}}$
$sin\theta = \frac{4}{4\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}}$
$sin\theta = \frac{4\sqrt{2}}{4\sqrt{4}}$
$sin\theta = \frac{4\sqrt{2}}{4(2)}$
$sin\theta = \frac{4\sqrt{2}}{8}$
$sin\theta = \frac{\sqrt{2}}{2}$
$2(sin\theta) = 2(\frac{\sqrt{2}}{2})$
$2sin\theta = \sqrt{2}$
$2sin\theta = 1.414$

z = a + bi
z = rcosθ + (rsinθ)i
z = r(cosθ + i sinθ)

z = 4 + 4i
z = 5.656cosθ + (5.656sinθ)i
z = 5.656(cosθ + i sinθ)
z = 5.656(cos45 + i sin45)

$\theta = tan^{-1}\frac{b}{a}$
$\theta = tan^{-1}\frac{4}{4}$
$\theta = tan^{-1}(1)$
$\theta = 45$

The polar form of 4 + 4i is approximately equal to 5.656(cos45 + i sin45).

5 0

3 years ago

A student scored in the 54th percentile on her Calculus exam. What does this student's score mean in relation to those of the ot

o-na [289]

The student's score was higher than 54% of the students who took the test. Then the correct option is C.

<h3>What is the percentage?</h3>

The quantity of anything is stated as though it were a fraction of a hundred.

A student scored in the 54th percentile on her Calculus exam.

Then the student's score mean in relation to those of the other test takers will be

Let the student got the lowest scored in calculus.

Then the student's score was higher than 54% of the students who took the test.

Then the correct option is C.

More about the percentage link is given below.

brainly.com/question/8011401

#SPJ1

4 0

2 years ago