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2 years ago

What is the expanded form of 397,567

Mathematics

1 answer:

NeX [460]2 years ago

4 0

Expanded Notation Form:

300,000

+ 90,000

+ 7,000

+ 500

+ 60

+ 7

Expanded Factors Form:

3 × 100,000

+ 9 × 10,000

+ 7 × 1,000

+ 5 × 100

+ 6 × 10

+ 7 × 1

Expanded Exponential Form:

3 × 105

+ 9 × 104

+ 7 × 103

+ 5 × 102

+ 6 × 101

+ 7 × 100

Word Form:

three hundred ninety-seven thousand five hundred sixty-seven

You might be interested in

X2+5x=3x+11 and solve by completing the square

Butoxors [25]

$x^2+5x=3x+11\\
x^2+2x-11=0\\
x^2+2x+1-12=0\\
(x+1)^2=12\\
x+1=\sqrt{12} \vee x+1=-\sqrt{12}\\
x=-1+2\sqrt3 \vee x=-1-2\sqrt3$

7 0

3 years ago

Adam exchanged British pounds for Swiss franc He changed £400 into 592 francs What was the exchange rate of British pounds to Sw

OLEGan [10]

Answer: 1 : 1.48

Step-by-step explanation:

Adam was able to change £400 into 592 francs which means that the British pound is stronger because it was able to buy more Swiss francs.

The exchange rate can be gotten using direct proportion:

400 : 592

1 : x

Cross multiply:

400x = 592

x = 592/400

x = 1.48

Exchange rate is:

= 1 : 1.48

5 0

2 years ago

Question #2 What is the difference?

e-lub [12.9K]

Answer:

B $\frac{b-10}{b-1}$

Step-by-step explanation:

In order to get the same denominator, we need to multiply the second fraction by (b+2) in the numerator and denominator.

We will end up in something like this : $\frac{b^{2} - 2b - 8 -6(b+2) }{(b-1)(b+2)}$

I just timed the second fraction by b+ 2 and then i added them together.

Therefore, we will get $\frac{b^{2} - 8b - 20}{(b-1)(b-2)}$

now factoring the numerator we will end like this

$\frac{(b-10)(b+2)}{(b-1)(b+2)}$

we will then end up with the answer.

Hope this helps.

3 0

2 years ago

Let $f(x) = 2x^2 + 3x - 9,$ $g(x) = 5x + 11,$ and $h(x) = -3x^2 + 1.$ Find $f(x) - g(x) + h(x).$

Viefleur [7K]

QUESTION 1

Given that:

$f(x)=2x^2+3x-9$ ,

$g(x)=5x+11$ ,

and

$h(x)=-3x^2+1$

Then;

$f(x)-g(x)+h(x)=2x^2+3x-9-(5x+11)+(-3x^2+1)$

$f(x)-g(x)+h(x)=2x^2+3x-9-5x-11-3x^2+1$

Group similar terms;

$f(x)-g(x)+h(x)=2x^2-3x^2+3x-5x-11-9+1$

Simplify;

$f(x)-g(x)+h(x)=-x^2-2x-19$

QUESTION 2

Given that;

$f(x)=4x-7$ .

$g(x)=(x+1)^2$

and

$s(x)=f(x)+g(x)$

Substitute the functions;

$s(x)=4x-7+(x+1)^2$

Substitute x=3

$s(3)=4(3)-7+(3+1)^2$

$s(3)=12-7+(4)^2$

$s(3)=5+16$

$s(3)=21$

QUESTION 3

Given:

$f(x)=3x+2$

$g(x)=x^2-5x-1$

$f(g(x))=f(x^2-5x-1)$

This implies that;

$f(g(x))=3(x^2-5x-1)+2$

Expand the parenthesis;

$f(g(x))=3x^2-15x-3+2$

$f(g(x))=3x^2-15x-1$

QUESTION 4

The given function is;

$f(x)=3(x-6)^2+1$

Let

$y=3(x-6)^2+1$

$\Rightarrow y-1=3(x-6)^2$

$\Rightarrow \frac{y-1}{3}=(x-6)^2$

$\Rightarrow \sqrt{\frac{y-1}{3}}=x-6$

$\Rightarrow x=6+\sqrt{\frac{y-1}{3}}$

The range is:

$\frac{y-1}{3}\ge0$

$y-1\ge0$

$y\ge1$

The interval notation is;

$[1,+\infty)$

6 0

2 years ago

State whether the triangles are similar. If so, write a similarity statement and the postulate or theorem you used.

never [62]

Answer:

Triangles ABC and MNO are similar by SSS

Step-by-step explanation:

we know that

If two triangles are similar, then the ratio of its corresponding sides is proportional

In this problem

If this problem the corresponding sides are

AB and MN

BC and NO

AC and MO

Verify if the corresponding sides are proportional

$\frac{AB}{MN}=\frac{BC}{NO}=\frac{AC}{MO}$

substitute the given values

$\frac{5}{7.5}=\frac{5}{7.5}=\frac{8}{12}$

$0.67=0.67=0.67$ ----- is true

When two triangles have corresponding sides with identical ratios , the triangles are similar by SSS Similarity

therefore

Triangles ABC and MNO are similar by SSS

8 0

2 years ago