Evaluate the following 1. sin(38°) 2. cos(51°) 3. tan(24°)

Give one number that makes the inequality 3x < 25 true

elena55 [62]

1 is the safest answer.

4 0

3 years ago

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The sign of the product of –35 and –625 is

Anarel [89]

Step-by-step explanation:

The mathematical sign for the operation is subtraction.

To Solve This You Will Need To;

1] The sign of the product of -35 and -625 is;

It's going to be;

-35--625

The negative sign will turn into addition sign before you can operate it. So it's going to be;

-35+625=590(positive)

It's just like subtracting 35 from 625.

2] The sign of the product of 263 and 0 is;

263-0

With this no quantity is going to be subtracted so the 263 will remain the same. 

So 263-0=263(positive)

3] The sign of the product of -21 and 451 is;

-21-451

With this you won't subtract but rather you'll add and when you add the answer is going to be -472

-472(negative)

4] The sign of the product of -350 and 89 is;

-350-89

With this you will add it but you won't subtract the negatives so it's going to be;

-350-89=-439(negative)

Hope I am Correct I didn't really understand your question well. But Good Luck:)

3 0

3 years ago

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Math-- Farmer Bill has 500 meters of fencing and wants to enclose a rectangular plot that borders on a river. If farmer Bill doe

bixtya [17]

Answer:

Required dimensions of the rectangle are L = 200 m, W = 100 m

The largest area that can be enclosed is 20,000 sq m.

Step-by-step explanation:

The available length of the fencing = 500 m

Now, Perimeter of a rectangle = SUM OF ALL SIDES = 2(L+B)

But, here once side of the rectangle is NOT FENCED.

So, the required perimeter

= Perimeter of Complete field - Boundary of 1 open side

= 2(L+ W) - L = 2W + L

Now, fencing is given as 500 m

⇒ 2W + L = 500

Now, to maximize the length and width:

put L = 200, W = 100

we get 2(W) +L = 2(200) + 100 = 500 m

Hence, required dimensions of the rectangle are L = 200 m, W = 100 m

The maximized area = Length x Width

= 200 m x 100 m = 20, 000 sq m

Hence, the largest area that can be enclosed is 20,000 sq m.

6 0

3 years ago

Agnes Hammer is a senior majoring in management science. She has been interviewing with several companies for a job when she gra

stiks02 [169]

Answer:

Mean = 30516.67

Standard deviation, s = 3996.55

P(x < 27000) = 0.0011518

Step-by-step explanation:

Given the data:

28500 35500 32600 36000 34000 25700 27500 29000 24600 31500 34500 26800

Mean, xbar = Σx / n = 366200 /12 = 30516.67

Standard deviation, s = [√Σ(x - xbar) / n-1]

Using calculator, s = 3996.55

The ZSCORE = (x - mean) / s/√n

Zscore = (27000 - 30516.67) / (3996.55/√12)

Zscore = - 3516.67 / 1153.7046

Zscore = - 3.048

P(x < 27000) = P(Z < - 3.049) = 0.0011518

3 0

3 years ago

What is the answer from "x=2" and graph each line and name two point on the line

Elena L [17]

i dont know srry

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4 0

3 years ago