1. first parabola is up, so a are going to be positive
y = a(x-r)(x-s),
roots -7,-3, so we can write y=a(x+7)(x+3) [1]
we can take point (-5,-2), substitute into equation [1], and find value of a
-2=a(-5+7)(-5+3)
-2=a*2*(-2)
a=1/2
so first parabola has an equation
y=1/2(x+7)(x+3)
2. second parabola
y=a(x-r)(x-s) roots are 2 and 4 so we ca write
y=a(x-2)(x-4) take point (3,4) and substitute into this equation
4 =a(3-2)(3-4)
4=-a
a=-4, and it will look down
y=-4(x-2)(x-4)
X ≥ -3
y ≥ 5x - 9
3x + y ≤ 15
3(-3) + (5x - 9) ≤ 15
-9 + (5x - 9) ≤ 15
(-9 - 9) + 5x ≤ 15
-18 + 5x ≤ 15
<u>+ 18 + 18</u>
<u>5x</u> ≤ <u>33</u>
5 5
x ≤ 6.6
y ≤ 5(6.6) - 9
y ≤ 33 - 9
y ≤ 24
(x, y) ≤ (6.6, 24)
The blank space in the task content should be filled with; a 270° rotation about point P.
<h3>What transformation is first to effect the image formation?</h3>
It follows from the transformation described in the task content that; Triangle KLM from which triangle K'L'M' is rotated 270 degrees about point P and then translated down and to the right.
It therefore follows from observation. that the first transformation is; a 270° rotation about point P.
Read more on transformation;
brainly.com/question/1462871
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Answer:
angle KMI = 136°
I hope this may be helpful
In geometry, a line segment is a part of a line that is bounded by two distinct end points, and contains every point on the line between its endpoints. A closed line segment includes both endpoints, while an open line segment excludes both endpoints; a half-open line segment includes exactly one of the endpoints.
Examples of line segments include the sides of a triangle or square.
More generally, when both of the segment's end points are vertices of a polygon or polyhedron, the line segment is either an edge (of that polygon or polyhedron) if they are adjacent vertices, or otherwise a diagonal. When the end points both lie on a curve such as a circle, a line segment is called a chord (of that curve).
So I think it would be 2
