B=48/7 you simplify 7/b(b) to 7b/6
Then multiply both sides by 6 so 8 x 6 =7b then simplify 8 x 6 =48
And divide both sides by 7 48\7 then switch sides b=48/7
The probability that at least two of the missiles hit the arsenal:
P ( x ≥ 2 ) = P ( x = 2 ) + P ( x = 3 )
P ( x = 2 ) = 0.75 · 0.85 · 0.1 + 0.85 · 0.9 · 0.25 + 0.75 · 0.9 · 0.15 =
= 0.06375 + 0.10125 + 0.19125 = 0.35625
P ( x = 3 ) = 0.75 · 0.85 · 0.9 = 0.57375
P ( x ≥ 2 ) = 0.35625 + 0.57375 = 0.93
Answer:
The probability is 0.93 or 93%.
Answer:
Step-by-step explanation:
Given function: 
To find 
, simply input 
into the function:
Answer:
2
Step-by-step explanation:
