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Anestetic [448]
3 years ago
9

Please solve 6+4/5b=9/10b

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
5 0
I think b = 1 over 60 
6+ 4 over 5b = 9 over 10b.
(6+ 4 over 5b)*10b = 9
30b + 4 over 5b*10b= 9 
(30b+4)*2=9
60b+8=9
60b=9-8
60b=1
b=1/60, b 0. 
b = 1/60 or 60. 
I could be wrong. 
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Lucy is a dress maker. She sews 4/7 of a dress in 3/4 hour. Lucy sews at a constant rate. At this rate, how many dresses does Lu
MAVERICK [17]

Answer:

16/21 dresses

Step-by-step explanation:

3/4 · k hours: 4/7 · k dresses for any constant k

If we want 1 hour, then k will need to be 4/3

4/3 × 4/3 hours: 4/7 × 4/3

1 hour = 16/21 dresses

7 0
3 years ago
Find the distance between these points. <br> A(5,8), B(-3,4)
konstantin123 [22]

Answer:

<u>Distance</u><u> </u><u>between</u><u> </u><u>the</u><u> </u><u>points</u><u> </u><u>is</u><u> </u><u>8</u><u>.</u><u>9</u><u>4</u><u> </u><u>units</u>

Step-by-step explanation:

General formula:

{ \boxed{ \bf{distance =  \sqrt{ {(x_{1} - x _{2} )}^{2} +  {(y _{1} - y _{2} ) }^{2}  } }}}

substitute:

{ \sf{ =  \sqrt{ {(5 - ( - 3))}^{2}  +  {(8 - 4)}^{2} } }} \\  = {  \sf{ \sqrt{64 + 16} }} \\  = { \sf{ \sqrt{80} }} \\  = 8.94 \: units

{ \underline{ \sf{ \blue{christ \: † \: alone}}}}

6 0
3 years ago
Read 2 more answers
Ella plans to make treats for her class.
PSYCHO15rus [73]

Answer:

2/3 * 25/1  = 50 / 3 = 16 66/100 = 16 4/25

Step-by-step explanation:

6 0
3 years ago
There are 4 people at a party. Consider the random variable X=’number of people having the same birthday ’ (match only month, N=
yulyashka [42]

Answer:

S = {0,2,3,4}

P(X=0) = 0.573 , P(X=2) = 0.401 , P(x=3) = 0.025, P(X=4) = 0.001

Mean = 0.879

Standard Deviation = 1.033

Step-by-step explanation:

Let the number of people having same birth month be = x

The number of ways of distributing the birthdays of the 4 men = (12*12*12*12)

The number of ways of distributing their birthdays = 12⁴

The sample space, S = { 0,2,3,4} (since 1 person cannot share birthday with himself)

P(X = 0) = \frac{12P4}{12^{4} }

P(X=0) = 0.573

P(X=2) = P(2 months are common) P(1 month is common, 1 month is not common)

P(X=2) = \frac{3C2 * 12P2}{12^{4} } + \frac{4C2 * 12P3}{12^{4} }

P(X=2) = 0.401

P(X=3) = \frac{4C3 * 12P2}{12^{4} }

P(x=3) = 0.025

P(X=4) = \frac{12}{12^{4} }

P(X=4) = 0.001

Mean, \mu = \sum xP(x)

\mu = (0*0.573) + (2*0.401) + (3*0.025) + (4*0.001)\\\mu = 0.879

Standard deviation, SD = \sqrt{\sum x^{2} P(x) - \mu^{2}}  \\SD =\sqrt{ [ (0^{2} * 0.573) + (2^{2}  * 0.401) + (3^{2} * 0.025) + (4^{2} * 0.001)] - 0.879^{2}}

SD = 1.033

4 0
4 years ago
Which are sums of perfect cubes? Check all that apply. 8x6 27 x9 1 81x3 16x6 x6 x3 27x9 x12 9x3 27x9.
Black_prince [1.1K]

The equations which are sums of perfect cubes are as follows;

\rm 8x^6+27x^9+1

\rm x^6+x^3

\rm 27x^9+x^{12}

<h3>Perfect cubes;</h3>

Perfect cubes are the numbers that are the triple product of the same number.

We have to determine

Which are sums of perfect cubes?

1. The given equation is \rm 8x^6+27x^9+1.

The equation can be written as;

\rm 8x^6+27x^9+1\\\\2^3(x^2)^3+3^3(x^3)^3+1^3

All the terms in the expression are can be represented as perfect cubes.

2.  The given equation is \rm 81x^3+16x^6.

The equation can be written as;

\rm 81x^3+16x^6\\\\9^2x^3+4^2(x^2)3

In this, all the terms are not perfect cubes, some of them are squares.

3. The given equation is \rm x^6+x^3.

The equation can be written as;

\rm x^6+x^3\\\\(x^2)^3+x^3

All the terms in the expression are perfect cubes.

4.  The given equation is \rm 27x^9+x^{12}.

The equation can be written as;

\rm 27x^9+x^{12}\\\\3^3(x^3)^3+(x^4)^3

All the terms in the expression are perfect cubes.

5.   The given equation is \rm 9x^3+27x^9.

The equation can be written as;

\rm 9x^3+27x^9\\\\3^2x^3+3^3(x^3)^3

In this, all the terms are not perfect cubes, some of them are squares too.

To know more about perfect cubes click the link given below.

brainly.com/question/4701925

5 0
2 years ago
Read 2 more answers
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