Centrifugation is used to separate the suspended particles in solution.
<u>Explanation:</u>
- The method of centrifugal action commonly referred to as "Centrifugation" is majorly used to effectively separate the suspended particles from the solution by means of rotating the sample at the maximum speed.
- When the samples gets rotated at the maximum speed the suspended particles settles down at the bottom and it can be filtered using the filter paper,thus resulting in the separation of suspended particles in the solution.
- However this techniques cannot be used for the substances dissolved in solution.
First, determine the amount of substance in moles by dividing the given amount in grams by the molar mass.
17.8 grams LiF x (1 mole / 25.94 grams LiF) = 0.686 moles LiF
Divide this amount of substance by the volume of the solution in liters.
molarity = 0.686 moles LiF / 0.915 L sol'n
The molarity is therefore, 0.75 M.
Answer: The molarity of
is 0.07 M
Explanation:
According to the neutralization law,
where,
= basicity
= 1
= molarity of
solution = ?
= volume of
solution = 25.0 ml
= acidity of
= 1
= molarity of
solution = 0.1000 M
= volume of
solution = 17.5 ml
Putting in the values we get:
Therefore, molarity of
is 0.07 M
Colligative properties calculations are used for this type of problem. Calculations are as follows:
ΔT(boiling point) = 101.02 °C - 100.0 °C= 1.02 °C
<span>ΔT(boiling point) = (Kb)m
</span>m = 1.02 °C / 0.512 °C kg / mol
<span>m = 1.99 mol / kg
</span><span>ΔT(freezing point) = (Kf)m
</span>ΔT(freezing point) = 1.86 °C kg / mol (<span>1.99 mol / kg)
</span>ΔT(freezing point) = 3.70 <span>°C
</span>Tf - T = 3.70 <span>°C
T = -3.70 </span><span>°C</span>