<u>Answer:</u> The molarity of Iron (III) chloride is 0.622 M.
<u>Explanation:</u>
Molarity is defined as the number of moles present in one liter of solution. The equation used to calculate molarity of the solution is:
Or,
We are given:
Mass of iron (III) chloride = 1.01 g
Molar mass of iron (III) chloride = 162.2 g/mol
Volume of the solution = 10 mL
Putting values in above equation, we get:
Hence, the molarity of Iron (III) chloride is 0.622 M.
The proper way to chemically write carbon dioxide is CO2
Answer:
Solid: calcium and potassium
Liquid: mercury and bromine
Gaseous: oxygen and fluorine
Explanation:
Matter exists in three different states namely: solid, gaseous and liquid. Elements that are found in nature are classified as matter. Since, these elements are grouped as matter, they can either be found as either solids, liquids or gases at normal temperature and pressure.
At normal temperature (20°C or 293K) and pressure (1 atm), the following elements are found to exists in the respective state of matter:
Solid: Calcium (Ca) and potassium (K)
Liquid: Mercury (Hg) and bromine (Br)
Gaseous: Oxygen (O) and fluorine (F)
We are going to use this formula:
E° = 0.0592/ n * ㏒K
when E° is the standard state cell potential
and n is number of moles of electrons transferred in the balanced equation
for the reaction of the cell.
Sr(s) + Mg2+ (aq) ↔ Sr2+(aq) + Mg(s)
we can get it by using the given balanced equation, we here have 2 electrons
transferred so, n = 2
and K the equilibrium constant = 3.69 x 10^17
so, by substitution:
∴ E° = 0.0592 / 2 * ㏒ (3.69 x 10^17)
= 0.52 V
