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shtirl [24]
3 years ago
14

A low level of carbon dioxide labeled with 14C is accidentally released into the atmosphere surrounding industrial workers as th

ey resume work following the lunch hour. Unknowingly, they breathe the contaminated air for 1 hour. Which of the following compounds will be radioactively labeled?
A) About one half of the carbon atoms of newly synthesized fatty acids.
B) All of the carbon atoms of newly synthesized fatty acid.
C) The carboxyl atom of newly synthesized fatty acids.
D) One half of the carbon atoms of newly synthesized acetyl CoA.
E) About one third of the carbons of newly synthesized malonyl CoA.
Chemistry
1 answer:
ivann1987 [24]3 years ago
7 0

Answer:

D) One half of the carbon atoms of newly synthesized acetyl CoA.

Explanation:

It will be radioactively labeled because Malonyl CoA which contains 3 Carbon molecule is synthesized from Acetyl CoA which has 2 Carbon molecule.

This happens with the addition of ‘CO2’ with the help of the enzyme called acetyl CoA carboxylase.

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F(x)=-1/x
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                                                          o
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←-------- -∞                                                               +∞           ----------→


g(x) is a radical square root  function, therefore the radicand have to be greater than o equal to "0"
3x-9≥0
3x≥9
x≥3

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.........................................................Ф--------------------------------
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(f/g)(x) = (-1/x) / (√(3x-9)) is a rational function with a square root in the denominator,also the square root don´t take the value of "0";
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The domain of the function (f/g)(x) only can take the values found in all three domains at once.
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............................................................0---------------------------------
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