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shtirl [24]
3 years ago
14

A low level of carbon dioxide labeled with 14C is accidentally released into the atmosphere surrounding industrial workers as th

ey resume work following the lunch hour. Unknowingly, they breathe the contaminated air for 1 hour. Which of the following compounds will be radioactively labeled?
A) About one half of the carbon atoms of newly synthesized fatty acids.
B) All of the carbon atoms of newly synthesized fatty acid.
C) The carboxyl atom of newly synthesized fatty acids.
D) One half of the carbon atoms of newly synthesized acetyl CoA.
E) About one third of the carbons of newly synthesized malonyl CoA.
Chemistry
1 answer:
ivann1987 [24]3 years ago
7 0

Answer:

D) One half of the carbon atoms of newly synthesized acetyl CoA.

Explanation:

It will be radioactively labeled because Malonyl CoA which contains 3 Carbon molecule is synthesized from Acetyl CoA which has 2 Carbon molecule.

This happens with the addition of ‘CO2’ with the help of the enzyme called acetyl CoA carboxylase.

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Which of the subshells below do not exist due to the constraints upon the angular momentum quantum number?A) 2dB) 2sC) 2pD) all
Gnom [1K]

Answer:

  • Option A): <em>Due to the constraints upton the angular momentum quantum number, the subshell </em><u><em>2d</em></u><em> does not exist.</em>

Explanation:

The <em>angular momentum quantum number</em>, identified with the letter l (lowercase L),  number is the second quantum number.

This number identifies the shape of the orbital or <em>kind of subshell</em>.

The possible values of the angular momentum quantum number, l, are constrained by the value of the principal quantum number n: l can take values from 0 to n - 1.

So, you can use this guide:

Principal quantum   Angular momentum         Shape of the orbital

number, n                 quantum number, l

         1                                      0                             s

         2                                     0, 1                          s, p

         3                                     0, 1, 2                      s, p, d

Hence,

  • <u>the subshell 2d (n = 2, l = 2) is not feasible</u>.

  • 2s (option B) is possible: n = 2, l = 0

  • 2p (option C) is possible: n = 2, l = 1

7 0
3 years ago
0.200 grams of HCl is dissolved in 0.801 grams water. The density of the solution formed is 1.10 g/mL. What is the molarity of t
alina1380 [7]

Answer:

M=6.03M

Explanation:

Hello,

In this case, since the molarity is computed by:

M=\frac{n_{solute}}{V_{solution}}

Whereas the solute is the hydrochloric acid, we compute the corresponding moles with its molar mass (36.45 g/mol):

n_{solute}=0.200gHCl*\frac{1molHCl}{36.45gHCl} =0.00549molHCl

Next, since the solution contains both HCl and water, we compute the volume in liters by using its density:

V_{solution}=(0.200+0.801)g*\frac{1mL}{1.10g} *\frac{1L}{1000mL} =9.1x10^{-4}L

Therefore, the molarity turns out:

M=\frac{0.00549mol}{9.1x10^{-4}L}\\ \\M=6.03M

Regards.

6 0
3 years ago
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Free_Kalibri [48]

Answer: they have a net positive charge

Explanation:

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By what factor does [h+] change for a ph change of 2.39 units.
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I belive the answer to your question would be 0
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