You have a right triangle situation here, and what you are looking for is the length of the hypotenuse. The leg perpendicular to the ground is 100, and the base angle that is NOT the right angle, is 65. So your equation is set up like this: sin 65 = 100/x. Rearrange that a bit to get x alone: x = 100/ sin 65. Make sure your calculator is in degree mode and solve for x. x = 110.34 feet of string.

5 0

3 years ago

Three students had $12.00 total and went to a snack bar where their bill was $8.57. They want to share equally the money that is

tamaranim1 [39]

Answer:

1.14

Step-by-step explanation:

Start=12.00

Change= 8.57

Finish= 3.43 ( 12.00-8.57)

Divide finish by 3 3.43/3= 1.14

there will be a remainder of 1 cent unless you wanna be technical it wold be

1.14333333333

8 0

4 years ago

In order to estimate the average time spent on the computer terminals per student at a local university, data were collected for

Setler [38]

Answer:

7) d)

standard error of the mean of one sample of 'n' observation = 0.20

8) a)

The margin of Error = 0.392

9) d

The 95% of confidence intervals are (8.61 , 9.39)

Step-by-step explanation:

solution:-

The Given data sample size 'n' = 81

Given Population standard deviation 'σ' = 1.8 hours

The standard error of the mean of one sample of 'n' observation is

Standard error (SE)

= $\frac{S.D}{\sqrt{n} }$

= σ / √n

= $\frac{1.8}{\sqrt{81} } =0.2$

standard error of the mean of one sample of 'n' observation = 0.20

Solution:-

The Given data sample size 'n' = 81

Given Population standard deviation 'σ' = 1.8 hours

Given the probability is 0.95

The z- score = 1.96 at 0.05 level of significance.

The margin of Error = $\frac{z_{0.95} S.D}{\sqrt{n} }$

= $\frac{1.96 (S.D)}{\sqrt{n} }$

= $\frac{1.96 (1.8)}{\sqrt{81} }$

= 0.392

The margin of Error = 0.392

Solution:-

The 95% of confidence intervals are

$(x^{-} - 1.96\frac{S.D}{\sqrt{n} } , x^{-} + 1.96\frac{S.D}{\sqrt{n} } )$

$(9 - 1.96\frac{1.8}{\sqrt{81} } , 9+ 1.96\frac{1.8}{\sqrt{81} } )$

(9 - 0.392 , (9 + 0.392)

(8.609 , 9.392)

The 95% of confidence intervals are (8.61 , 9.39)

4 0

3 years ago