Each boy in a class has 7 pockets and each girl in that class has 11 pockets. How many boys and how many girls are there in this
2 answers:
Answer: There are 10 boys and 7 girls in the class.
Step-by-step explanation:
Let x be the number of boys and y be the number of girls then according to the question we have the following equations :-
The value of y from (1) will be
, substitute this in equation (2), we get
∴
Hence, there are 10 boys and 7 girls in the class.
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Answer:
C
Step-by-step explanation:
Calculate AC using Pythagoras' identity in ΔABC
AC² = 20² - 12² = 400 - 144 = 256, hence
AC = = 16
Now find AD² from ΔACD and ΔABD
ΔACD → AD² = 16² - (20 - x)² = 256 - 400 + 40x - x²
ΔABD → AD² = 12² - x² = 144 - x²
Equate both equations for AD², hence
256 - 400 + 40x - x² = 144 - x²
-144 + 40x - x² = 144 - x² ( add x² to both sides )
- 144 + 40x = 144 ( add 144 to both sides )
40x = 288 ( divide both sides by 40 )
x = 7.2 → C