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3 years ago

What is the equation for the line of reflection?x = 6y = 6y = xy = 2

Mathematics

2 answers:

umka2103 [35]3 years ago

4 0

X=6y is the answer......

olchik [2.2K]3 years ago

4 0

Answer:

x=y is the answer... hope this helps you ;D

Step-by-step explanation:

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Nola Giles down a trail at a steady rate for 10 minutes. Her change in elevation was -200 feet. Then she continued to hike down

lions [1.4K]

Her fastest change in elevation was -200 feet in 10 minutes. She was going at a rate of 20 fpm (feet per minute) compared to 15 fpm.

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3 years ago

Hope an expert can help with this

Citrus2011 [14]

For Range you take the biggest number and subtract it with the smallest. So:

January = E14,000

Febuary = E9,000

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All Three Months = E17,000

Hope this helps,pleeease vote as brainliest!

5 0

3 years ago

Please helpp<br> . What is the area of the blue figure? *

antiseptic1488 [7]

Answer:

465.5

Step-by-step explanation:

If you plug in the numbers into the formula.

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3 0

3 years ago

Read 2 more answers

For which value of x must the expression √37x be further simplified?

vekshin1

Answer:

37x

Step-by-step explanation:

Since it has a square root you can square it to get rid of it so your final answer is 37x

5 0

3 years ago

1. A report from the Secretary of Health and Human Services stated that 70% of single-vehicle traffic fatalities that occur at n

Nuetrik [128]

Using the binomial distribution, it is found that there is a 0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

For each fatality, there are only two possible outcomes, either it involved an intoxicated driver, or it did not. The probability of a fatality involving an intoxicated driver is independent of any other fatality, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
n is the number of trials.
p is the probability of a success on a single trial.

In this problem:

70% of fatalities involve an intoxicated driver, hence $p = 0.7$ .

A sample of 15 fatalities is taken, hence $n = 15$ .

The probability is:

$P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)$

Hence

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{15,10}.(0.7)^{10}.(0.3)^{5} = 0.2061$

$P(X = 11) = C_{15,11}.(0.7)^{11}.(0.3)^{4} = 0.2186$

$P(X = 12) = C_{15,12}.(0.7)^{12}.(0.3)^{3} = 0.1700$

$P(X = 13) = C_{15,13}.(0.7)^{13}.(0.3)^{2} = 0.0916$

$P(X = 14) = C_{15,14}.(0.7)^{14}.(0.3)^{1} = 0.0305$

$P(X = 15) = C_{15,15}.(0.7)^{15}.(0.3)^{0} = 0.0047$

Then:

$P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) = 0.2061 + 0.2186 + 0.1700 + 0.0916 + 0.0305 + 0.0047 = 0.7215$

0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

A similar problem is given at brainly.com/question/24863377

5 0

3 years ago