Help needed quick. I attacked the picture plz look
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F(x)=10-16/x
f'(x)=16/x^2
f'(c)=16/c^2
f(8)=10-16/8=10-2=8
f(2)=10-16/2=10-8=2
4∈[2,8] is the required point.
f'(x)=16/x^2
f'(c)=16/c^2
f(8)=10-16/8=10-2=8
f(2)=10-16/2=10-8=2
4∈[2,8] is the required point.
Answer:
Step-by-step explanation:
Let be the greater number and
be the smaller number. We know that their difference is 15, so we have
Then, we have the following information: if we add twice the greater (2x) and 8 (2x+8), the result is 3 times the lesser (3y) minus four (3y-4). So, we have
So, we have the follwing system:
From the first equation, we can derive , and substitute this expression in the second equation to get
Substitute this value for y in the first equation to get