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fomenos
3 years ago
13

If i= square root of -1, the I to the power of 2= ?

Mathematics
1 answer:
MAVERICK [17]3 years ago
8 0

Answer:

the answer is -1

Step-by-step explanation:

because well i don't know how to explain sorry im not very good at explaining this type of stuff but i know its the answer.

If brainiest is earned its greatly appreciated

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In my town, gas prices are always listed to the thousandths place. Since the smallest coin we have is the penny, we have to roun
AlladinOne [14]

Answer:

$8.16

Step-by-step explanation:

6 0
3 years ago
Two sections of a class took the same quiz. Section A had 15 students who had a mean score of 80, and Section B had 20 students
Ksju [112]

Answer:

86

Step-by-step explanation:

In this question, we are asked to calculate the average mean score for a group of students split into two different emerging groups.

We calculate the total score for each of the groups. This is done by multiplying the average score by the number of students.

Total score of section A is 15 * 80 = 1,200

For section B, total score is 20 * 90 = 1,800

Overall score is thus 1200 + 1800 = 3000

We add the scores together and divide by the total number of students in both sections

Average score is thus 3000/35 = 85.71 which is approximately 86

3 0
3 years ago
Help please, I'm desperate!
Luden [163]
B. 2.8
Because, 4-1.2=2.8
8 0
3 years ago
Read 2 more answers
I need help with number 8
murzikaleks [220]
Since we know what he earns hourly, and his sales, we can figure out his full gross pay for the week.
As so:

We can set up an equation like this:
<em>h</em> = hours
<em>s</em> = sales
9.60h + 5%s

Now, we substitute.
9.60(35) + 5%(230)

Next, solve.
336.00 + 11.50
$347.50

$347.50 was Glen's gross pay for the week.

Hope I could help! If my math is wrong, or I did not provide the answer you were looking for, let me know! However, if I did well, please consider marking as <em>Brainliest!
</em>Have a good one!

8 0
3 years ago
Read 2 more answers
(a) Starting with the geometric series [infinity] xn n = 0 , find the sum of the series [infinity] nxn − 1 n = 1 , |x| &lt; 1.
Mila [183]

Let <em>f(x)</em> be the sum of the geometric series,

f(x)=\displaystyle\frac1{1-x} = \sum_{n=0}^\infty x^n

for |<em>x</em>| < 1. Then taking the derivative gives the desired sum,

f'(x)=\displaystyle\boxed{\dfrac1{(1-x)^2}} = \sum_{n=0}^\infty nx^{n-1} = \sum_{n=1}^\infty nx^{n-1}

5 0
2 years ago
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