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olga nikolaevna [1]
3 years ago
15

Calculate the values of the expression below 2 ( 3 (5 + 2) -1)​

Mathematics
2 answers:
Otrada [13]3 years ago
7 0

Answer:

= 40

Step-by-step explanation:

2 ( 3 (5 + 2) -1)

= 2 * 20

= 40

Tema [17]3 years ago
7 0

Answer:

<h2>40</h2>

Step-by-step explanation:

2\left(3\left(5+2\right)-1\right)\\\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Calculate\:within\:parentheses}\:\left(3\left(5+2\right)-1\right)\:\\\\:\quad 20\\\\=2\times \:20\\\\= 40

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9. Given the point (6,-8) values of the six trig function.
lozanna [386]

Answer:

Here's what I get.

Step-by-step explanation:

9. (6, -8)

The reference angle θ is in the fourth quadrant.

∆AOB is a right triangle.

OB² = OA² + AB² = 6² + (-8)² = 36 + 64 = 100

OB = √100 = 10  

\sin \theta = \dfrac{-8}{10} = -\dfrac{4}{5}\\\\\cos \theta =\dfrac{6}{10} = \dfrac{3}{5}\\\\\tan \theta = \dfrac{-8}{6} = -\dfrac{4}{3}\\\\\csc \theta = \dfrac{10}{-8} = -\dfrac{5}{4}\\\\\sec \theta = \dfrac{10}{6} = \dfrac{5}{3}\\\\\cot \theta = \dfrac{6}{-8} = -\dfrac{3}{4}

10. cot θ = -(√3)/2

The reference angle θ is in the second quadrant.

∆AOB is a right triangle.

OB² = OA² + AB² = (-√3)² + (2)² = 3 + 4 = 7

OB = √7

\sin \theta = \dfrac{2}{\sqrt{7}} = \dfrac{2\sqrt{7}}{7}\\\\\cos \theta = \dfrac{-\sqrt{3}}{\sqrt{7}} = -\dfrac{\sqrt{21}}{7}\\\\\tan \theta = \dfrac{2}{-\sqrt{3}} = -\dfrac{2\sqrt{3}}{3}\\\\\csc \theta = \dfrac{\sqrt{7}}{2} \\\\\sec \theta = \dfrac{\sqrt{7}}{-\sqrt{3}} = -\dfrac{\sqrt{21}}{3}\\\\\cot \theta = -\dfrac{\sqrt{3}}{2}

3 0
3 years ago
What is the interquartile range of this data?
slava [35]
IQR=36-16.. which would give you 20!
7 0
3 years ago
Read 2 more answers
What is the rule for multiplying and dividing integers
tankabanditka [31]

Answer:

When you multiply two integers with different signs, the result is always negative. Just multiply the absolute values and make the answer negative. When you divide two integers with the same sign, the result is always positive. Just divide the absolute values and make the answer positive.

Step-by-step explanation:

its easy as 1, 2, 3  lol

8 0
3 years ago
Read 2 more answers
How do I solve 3+k/14=4
Sedaia [141]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{k = 53}}}}}

Step-by-step explanation:

\bigstar{ \sf{   \:  \: \frac{3 + k}{14} = 4}}

\tt{Step \: 1 \: } : Do cross multiplication

\hookrightarrow{ \sf{3 + k = 4 \times 14}}

\tt{Step \: 2} : Multiply the numbers : 4 and 14

\hookrightarrow{ \sf{3 + k = 56}}

\tt{Step \: 3 \: } Move 3 to right hand side and change it's sign

\hookrightarrow{ \sf{k = 56 - 3}}

\tt{Step \: 4 \: } Subtract 3 from 56

\hookrightarrow{ \sf{k = 53}}

The value of k is 53

Hope I helped!

Best regards! :D

~TheAnimeGirl

8 0
3 years ago
Read 2 more answers
nora has 3/4 as many books as victor. let v represent the number of books victor has. create an expression to represent the numb
xxTIMURxx [149]

Answer:

N = \frac{3}{4} * v

Step-by-step explanation:

Since the value that we are provided is a fraction that is tied to the number of books that Victor has, we would simply need to multiply this fraction by the total number of books that Victor has. This value is represented by the variable v while the total number of books that Nora has is represented by the variable N. Therefore, the expression would be the following

N = \frac{3}{4} * v

4 0
3 years ago
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