A circle has a diameter with endpoints of (-2, 8) and (6, 4). What is the center of the circle?

Mathematics

2 answers:

finlep [7]3 years ago

8 0

2,6 should be correct

BARSIC [14]3 years ago

5 0

The midpoint of the two points will be the center of the circle. The midpoint is simply the average of the endpoints coordinates...

((6-2)/2, (4+8)/2)

(2, 6) is the center of the circle.

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Please help on this problem

Harlamova29_29 [7]

Answer: EP is 12 and EO is about 10.91.

To find the length of EP, we can use the Pythagorean Theorem with the 2 legs of the right triangle it would form, EC and CP. CP would be 5 because it is the midpoint of the side.

5^2 + (EP)^2 = 13^2
EP = 12

Now, to find EO, we write and solve another Pythagorean Theorem equation using 12 for EP.

5^2 + (EO)^2 = 12^2
EO equals the square root of 119 or about 10.91.

6 0

3 years ago

Find the Missing Numerator and Denominator

n200080 [17]

Answer:

missing denominator: 5

missing numerator: 3

Step-by-step explanation:

You know the product of fractions is formed by multiplying numerators and multiplying denominators.

$\dfrac{3}{d}\times\dfrac{n}{4}=\dfrac{3n}{4d}=\dfrac{9}{20}$