Answer:
40951
Step-by-step explanation:
Using the principles of inclusion - Exclusion
Where C(n,r)=n!/(n-r)!r!
Total elements in the five sets including number repetition is given as (10000)×C(5, 1) =10000× 5!/(5-1)!1!=10000×5=50000
Total Number of elements in each pair including number repetition of sets is given as
=(1000) × C(5, 2) =10000
Number of elements in each triple of sets is given as
=(100) × C(5, 3) =1000
Number of elements in every four sets
=(10) × C(5, 4)=50
Number of elements in every one set
(1) × C(5, 5)=1
Therefore total number of unique elements=50000-10000+1000-50+1
=40951
The verbal expression for 2m is two meters
Step-by-step explanation:
given a normal distribution with the given parameters the probability (= the % of the area of the distribution curve) for a number to be between 203 and 1803 is
0.9987
so, 99.87% of all numbers are expected to be in that range.
for 350,000 numbers that means
350,000×0.9987 = 349,545 numbers are expected to be between 203 and 1803.
There are six vowels and 4 card suits
Each vowel can pick from 4 suits so 4*6=24
24 outcomes
Answer:
Step-by-step explanation:
4.30/40=$0.1075
Hope this helps :)
