Answer
y = 1.4
I think it will help you..............
Answer:
The answers to the questions are;
(a) P(At least 1 defective)
= 0.9883.
(b) P(At least 1 defective)
= 0.6409.
Step-by-step explanation:
There are 110 cards and 20 defectives.
a) The probability of at least one defective is given by
P(At least 1 defective) = 1 - P(0 defective)
P(0 defective) = 20C0 × (90C0)/(110C20) = 0.0116
1 - 0.0116 = 0.9883
b) For a set of 110 boards that has 5 defective and 105 non-defective
P(At least 1 defective) = 1 - P(0 defective)
P(0 defective) = (20C0)(90C5)/(110C5) = 0.35909
1-0.35909
= 0.6409
Answer:
2f + 16
Step-by-step explanation:
Answer:
the partial pressure of 02is 17.9
Answer: Rational numbers have decimal expansions that repeat or terminate.
Step-by-step explanation:
The explanation of this is the non-terminating but repeating decimal expansion means that although the decimal representation has an infinite number of digits, there is a repetitive pattern to it. The rational number whose denominator is having a factor other than 2 or 5, will not have a terminating decimal number as the result.
