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Lady bird [3.3K]
3 years ago
15

A system of equations has no solutionm if y=8x+7 is one of the equations whocu cpuld be the other equation

Mathematics
1 answer:
Alex Ar [27]3 years ago
4 0
Idk what the answer is
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Asanji spent half of his weekly allowance at the movies to earn more money his parents let him wash the car for $8 what is his w
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(2x+9y-4) - (+5y+2)
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2x+9y-4-5y-2       2x+4y-6
8 0
3 years ago
At a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective pa
11Alexandr11 [23.1K]

Answer:

Probability that fewer than 2 of these parts are defective is 0.604.

Step-by-step explanation:

We are given that at a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective parts 19% of the time.

A random sample of 7 parts produced by this machine is chosen.

The above situation can be represented through Binomial distribution;

P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....

where, n = number of trials (samples) taken = 7 parts

            r = number of success = fewer than 2

           p = probability of success which in our question is % of defective

                 parts produced by one of the machine, i.e; 19%

<em>LET X = Number of parts that are defective</em>

<u>So, it means X ~ Binom(n = 7, p = 0.19)</u>

Now, probability that fewer than 2 of these parts are defective is given by = P(X < 2)

    P(X < 2) = P(X = 0) + P(X = 1)

                  =  \binom{7}{0}\times 0.19^{0} \times (1-0.19)^{7-0}+ \binom{7}{1}\times 0.19^{1} \times (1-0.19)^{7-1}

                  =  1 \times 1 \times 0.81^{7} +7 \times 01.9^{1} \times 0.81^{6}

                  =  <u>0.604</u>

<em>Therefore, the probability that fewer than 2 of these parts are defective is 0.604.</em>

8 0
3 years ago
The perimeter of a rectangle is 58.8 km, and its diagonal length is 21 km. Find its length and width
Oliga [24]
Length: 16.8 or 12.6
Diagonal 21
5 0
3 years ago
Read 2 more answers
What is the radius of a circle whose equation is x^2+y^2-10x+6y + 18=0
rjkz [21]

Answer:

Explanation:

We must write this equation in the form

(

x

−

a

)

2

+

(

y

−

b

)

2

=

r

2

Where

(

a

,

b

)

are the co ordinates of the center of the circle and the radius is

r

.

So the equation is

x

2

+

y

2

−

10

x

+

6

y

+

18

=

0

Complete the squares so add 25 on both sides of the equation

x

2

+

y

2

−

10

x

+

25

+

6

y

+

18

=

0

+

25

=

(

x

−

5

)

2

+

y

2

+

6

y

+

18

=

0

+

25

Now add 9 on both sides

(

x

−

5

)

2

+

y

2

+

6

y

+

18

+

9

=

0

+

25

+

9

=

(

x

−

5

)

2

+

(

y

+

3

)

2

+

18

=

0

+

25

+

9

This becomes

(

x

−

5

)

2

+

(

y

+

3

)

2

=

16

So we can see that the centre is

(

5

,

−

3

)

and the radius is

√

16

or 4

6 0
3 years ago
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