Which set of ordered pairs represents a function? {(0, 1), (1, 3), (1, 5), (2, 8)} {(0, 0), (1, 2), (2, 6), (2, 8)} {(0, 0), (0,
11111nata11111 [884]
Answer: {(0, 2), (1, 4), (2, 6), (3, 6)}
Step-by-step explanation:
For a relation to be considered a function, each x-value needs to have one corresponding y-value--it cannot have more than 1.
Since all the other sets of ordered pairs feature points with two x-values with different y-values, the set above is the only function of the provided options.
Answer:
Step-by-step explanation:
4) x² - 14x + 48
We would find two numbers such that their sum or difference is -14x and their product is 48x².
The two numbers are - 6x and - 8x. Therefore,
x² - 6x - 8x + 48
x(x - 6) - 8(x - 6)
(x - 8)(x - 6)
5) 2x² + 21x - 11
We would find two numbers such that their sum or difference is 21x and their product is - 22x².
The two numbers are 22x and - x. Therefore,
2x² + 22x - x - 11
2x(x + 11) - 1(x + 11)
(2x - 1)(x + 11)
6) 5a² - 125
5 is a common factor. So we would factorize 5. It becomes
5(a² - 25)
Simplifying further, it becomes
5(a + 5)(a - 5)
Answer:
They will meet in 5:30.
Step-by-step explanation:
'Cause you have to fin the LCM (least common multiple). And in this case the LCM is 30.
The answer to this question would be D. 3(x)-3(9)
Answer:
Undefined
Step-by-step explanation:
No multiplicative inverse exists for 0
