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disa [49]
3 years ago
10

18.9 = 0.580/V Pls answer

Chemistry
1 answer:
Delvig [45]3 years ago
6 0

Answer:

the answer is V=0.0306878

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Using the following equation how many moles of KClO3 are required if 6.9 moles of O2 are formed?
Nimfa-mama [501]

Answer:

Number of moles of KClO3 required to produce 6.9 moles of oxygen gas is 4.6 moles.

Explanation:

The decomposition of potassium trioxochlorate(v) by heat to produce potassium chloride and oxygen gas is given by the balanced chemical equation below;

2KClO3(s) ----> 2KCl(s) + 3O2(g)

From the equation of the reaction, 2 moles of KClO3 produces 3 moles of oxygen gas when it decomposes under standard conditions of temperature and pressure.

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is 2:3

When 6.9 moles of oxygen gas is produced, (2/3) * 6.9 moles of KClO3 will be required = 4.6 moles of KClO3

Therefore, number of moles of KClO3 required to produce 6.9 moles of oxygen gas is 4.6 moles

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