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Neporo4naja [7]
3 years ago
5

Calcule la masa de aluminio (Al) producido por una electrolisis de AlCl3 fundido en una hora usando una corriente de 7.2 A

Chemistry
1 answer:
Anestetic [448]3 years ago
4 0

i love carlos

but not u

in PUBG carlo

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Wht is a electric charge
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Answer:

Electric charge is the physical property of matter that causes it to experience a force when placed in an electromagnetic field. There are two types of electric charge: positive and negative (commonly carried by protons and electrons respectively).

Explanation:

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6 0
4 years ago
How many moles are there in<br> 15 grams of:<br> CaCO3<br> 204 grams of:<br> Al203
DerKrebs [107]

1) moles = mass/mR

CaCO3 Mr = 40 + 12 + (16×3)

= 52 + 48

= 100

mass = 15

so the moles would be 15 ÷ 100

which is 0.15 moles of CaCO3

2) moles = mass ÷ Mr

Mr of Al2O3 = 27 + (16×3)

= 27 + 48

= 75

mass = 204

so the moles would be 204/75 which is 2.72 moles of Al2O3

3 0
3 years ago
A neutron collides with a nitrogen atom, resulting in a transmutation. Balance the equation. Superscript 1 Subscript 0 Baseline
o-na [289]

Answer:

A is 14

Z is 6

X is C

Explanation:

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7 0
3 years ago
The equilibrium system N2O4(g) 2NO2(g) was established in a 1.00-liter vessel. Upon analysis, the following information was foun
julsineya [31]
For the reaction, the equilibrium constant equation will be:

Kc = [NO₂]² / [N₂O₄]
Kc = (0.5)² / 0.025
Kc = 10

The answer is C.
3 0
3 years ago
Read 2 more answers
Certain metal oxide has the formula MO where M denotes the metal. A 73.35−g sample of the compound is strongly heated in an atmo
pshichka [43]

Answer:

atomic mass 112.4 and Cadmium (Cd)

Explanation:

You have 73.35 g of MO.

After the reaction the O is removed and you only have M which the mass is 64.21 g.

With that you can calculate the mass of O removed:

Mass of O = 9.14 g

Mass = AM * moles ; (AM : Atomic Mass)

9.14 = 16 * moles

moles = 9.14 / 16

moles = 0.57125

The formula of the metal oxide is MO, meaning it has 1 mole of M per mole of O. 73.35 had 0.57125 moles of O, then it also had 0.57125 moles of M, and the remaining mass of 64.21 g represents those moles

Mass = AM * moles ; (AM : Atomic Mass)

64.21 = AM * 0.57125

AM = 64.21/0.57125 = 112.4 amu

The metal with an atomic mass of 112.4 is Cadmium (Cd), therefore the metal oxide is CdO

7 0
3 years ago
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