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Mama L [17]
3 years ago
9

What atoms ionization energy is greater than phosphorus

Chemistry
1 answer:
Liono4ka [1.6K]3 years ago
8 0

Ionization energy is defined as the minimum amount of energy required to knock out the electron from valence shell of an atom.

Trends in Period:

                           Ionization energy increases from left to right across the periodic table. This is because from left to right along the period the nuclear charge increases and the number of shells remain constant.

Trends in Groups:

                            Ionization energy decreases from top to bottom along the group. This is because down the group the number of shells increases and hence, the shielding effect increases shielding the valence electrons therefore, valence electrons are easily knocked out.

<h3>Conclusion:</h3>

                     So, we can conclude that elements at right to Phosphorous and above Phosphorous will have greater Ionization energies as compared to Phosphorous. Examples,

At right to Phosphorous;

                                              Sulfur

                                              Chlorine

                                              Argon

At the top of Phosphorous;

                                             Nitrogen

                                              Oxygen

                                              Fluorine

                                              Neon

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The recommended daily allowance (rda of calcium is 1.2 g. calcium carbonate contains 12.0% calcium by mass. how many grams of ca
defon
1) Calcium carbonate contains 40.0% calcium by weight.
M(CaCO₃)=100.1 g/mol
M(Ca)=40.1 g/mol
w(Ca)=40.1/100.1=0.400 (40.0%)!

2) Mass fraction of this is excessive data.

3) The solution is:

m(Ca)=1.2 g

m(CaCO₃)=M(CaCO₃)*m(Ca)/M(Ca)

m(CaCO₃)=100.1g/mol*1.2g/40.1g/mol=3.0 g
4 0
3 years ago
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To completely convert 9. 0 moles of hydrogen gas (h2) to ammonia gas, how many moles of nitrogen gas (n2) are required?
evablogger [386]

To completely convert 9. 0 moles of hydrogen gas (h2) to ammonia gas, 3.0 moles of nitrogen gas (n2) are required.

<h3>What are moles?</h3>

The mole is a SI unit of measurement that is used to calculate the quantity of any substance.

<h3 />

The given reaction is \rm  N_2(g) + 3H_2(g) \rightarrow 2NH_3(g)

By the stoichiometry rule of ratio hydrogen: nitrogen

3 : 1

The reacted moles of nitrogen is equals to H/3 moles of reacted hydrogen

So, moles of nitrogen  

\rm Moles\; of\; nitrogen = \dfrac{9.0 }{3} =3.0\;mol

Thus, 3.0 moles of nitrogen gas (n2) are required.

Learn more about moles

brainly.com/question/26416088

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3 0
2 years ago
Which best explains why the trend in noble gas boiling points increases down the group?A) increasing dispersion interactions B)
zhenek [66]

Answer:

A) increasing dispersion interactions

Explanation:

Polarizability allows gases containing atoms or nonpolar molecules (for example,  to condense. In these gases, the most important kind of interaction produces <em>dispersion forces</em>, <em>attractive forces that arise as a result of temporary dipoles induced in atoms or molecules.</em>

<em>Dispersion forces</em>, which are also called <em>London forces</em>, usually <u>increase with molar mass because molecules with larger molar mass tend to have more electrons</u>, and <u>dispersion forces increase in strength with the number of electrons</u>. Furthermore, larger molar mass often means a bigger atom whose electron distribution is more easily disturbed because the outer electrons are less tightly held by the nuclei.

Because the noble gases are all nonpolar molecules, <u>the only attractive intermolecular  forces present are the dispersion forces</u>.

8 0
3 years ago
You know that 8.9 moles of solute particles are dissolved in that liquid solution. If the molarity of the solution is 25 M, how
pychu [463]

Answer:

V = 0.356 L

Explanation:

In this case, we need to use the following expression:

M = n/V (1)

Where:

M: molarity of solution (mol/L or M)

n: moles of solute (moles)

V: Volume of solution (Liters)

From these expression, we can solve for V:

V = n/M  (2)

Now, replacing the given data we can solve V:

V = 8.9 / 25

V = 0.356 L

5 0
3 years ago
Which determines the reactivity of an alkali metal?
adelina 88 [10]

Answer:

its ability to lose electron

3 0
3 years ago
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