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Mars2501 [29]
3 years ago
12

How do I 'simplify the square root of 50xy^2?

Mathematics
1 answer:
insens350 [35]3 years ago
4 0

the square and the square root should cancel so your left with only 50xy

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Why did the kindergartener take her books to the zoo
Shalnov [3]
So the kindergartner could show animals pictures. XD JK 

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3 years ago
a light switch works 25% of the time, how many times does it not work if switched on 64 times in a week
alexira [117]
25% of 64 is 16
\frac{25}{100}  =  \frac{x}{64}  \\ x =  \frac{64 \times 25}{100}  =  \frac{1600}{100}  = 16
it will work properly 16 times
64 - 16 = 48
it will not work 48 times
hope this helps
7 0
3 years ago
14-21 in lowest terms
BaLLatris [955]
-7 is the answer to that
8 0
3 years ago
The wavelength of violet light is 4.0 x 10^−7 m. The wavelength of red light is 6.5 x 10^−7 m. How much longer is the wavelength
AnnyKZ [126]

Answer:

A 2.5 × 10^–7 m

Step-by-step explanation:

Given

wavelength of violet light = 4.0 x 10^−7 m.

The wavelength of red light = 6.5 x 10^−7 m

To find the how much longer is wavelength of red light than violet light we have to find difference of wavelength of red and violet light

Difference in  wavelength of red light and violet light =

wavelength of red light -wavelength of violet light

                         = 6.5 x 10^−7 m - 4.0 x 10^−7 m

Difference in  wavelength of red light and violet light = (6.5 - 4.0)*10^−7 m

Difference in  wavelength of red light and violet light =2.5 x 10^−7 m

Thus,

wavelength of red light is 2.5 x 10^−7 m longer than wavelength of violet light

option A

8 0
3 years ago
Given that f(x) = x + 3<br> a) Find f(2)
Nataly_w [17]

{ \qquad\qquad\huge\underline{{\sf Answer}}}

Here we go ~

In the above question, it is given that :

\qquad \sf  \boxed{ \sf f(x) =  \frac{x + 3}{2} }

A.) Find f(2) :

\qquad \sf  \dashrightarrow \: f(2) =  \dfrac{2 + 3}{2}

\qquad \sf  \dashrightarrow \: f(2) =  \dfrac{5}{2}

or

\qquad \sf  \dashrightarrow \: f(2) = 0.5

B.) Find { \sf {f}^{-1}(x) } :

\qquad \sf  \dashrightarrow \: let \: y = f (x)

so, we can write it as :

\qquad \sf  \dashrightarrow \: y =  \dfrac{x + 3}{2}

\qquad \sf  \dashrightarrow \: 2y = x + 3

\qquad \sf  \dashrightarrow \: x = 2y - 3

Now, put x = { \sf {f}^{-1}(x) }, and y = x and we will get our required inverse function ~

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(x) = 2x- 3

C.) Find { \sf {f}^{-1}(12) } :

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 2(12)- 3

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 36- 3

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 33

7 0
1 year ago
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