Answer:
The capacity of the container is 2546.78 cm³.
Step-by-step explanation:
The volume of the frustum of a cone is:
![\text{Volume}=\frac{\pi h}{3}\cdot[R^{2}+Rr+r^{2}]](https://tex.z-dn.net/?f=%5Ctext%7BVolume%7D%3D%5Cfrac%7B%5Cpi%20h%7D%7B3%7D%5Ccdot%5BR%5E%7B2%7D%2BRr%2Br%5E%7B2%7D%5D)
The information provided is:
r = 16/2 = 8 cm
R = 24/2 = 12 cm
h = 8 cm
Compute the capacity of the container as follows:
![\text{Volume}=\frac{\pi h}{3}\cdot[R^{2}+Rr+r^{2}]](https://tex.z-dn.net/?f=%5Ctext%7BVolume%7D%3D%5Cfrac%7B%5Cpi%20h%7D%7B3%7D%5Ccdot%5BR%5E%7B2%7D%2BRr%2Br%5E%7B2%7D%5D)
![=\frac{\pi\cdot8}{3}\cdot[(12)^{2}+(12\cdot 8)+(8)^{2}]\\\\=\frac{8\pi}{3}\times [144+96+64]\\\\=\frac{8\pi}{3}\times304\\\\=2546.784445\\\\\approx 2546.78](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%5Cpi%5Ccdot8%7D%7B3%7D%5Ccdot%5B%2812%29%5E%7B2%7D%2B%2812%5Ccdot%208%29%2B%288%29%5E%7B2%7D%5D%5C%5C%5C%5C%3D%5Cfrac%7B8%5Cpi%7D%7B3%7D%5Ctimes%20%5B144%2B96%2B64%5D%5C%5C%5C%5C%3D%5Cfrac%7B8%5Cpi%7D%7B3%7D%5Ctimes304%5C%5C%5C%5C%3D2546.784445%5C%5C%5C%5C%5Capprox%202546.78)
Thus, the capacity of the container is 2546.78 cm³.
Answer:
2x(x+6)(x-6)
Step-by-step explanation:
2x³-72
2x(x²-36)
2x(x+6)(x-6)
Answer:
22, 17, and 44.
Step-by-step explanation:
So what you do is you will have three equations that we will put together.
1. x. The first number is x because they don't give us anything about it.
2. x-5. It says that the second number is 5 less than the first number.
3. 2x. It says that the third number is 2 times the first number.
<em>x+x-5+2x=83. </em>
<em>4x-5=83.</em>
<em>4x=88.</em>
<em>x=22. </em>
That is the first number. To find the second and third, you will plug 22 into the x.
2. 22-5=17.
3. 2(22)=44.
22, 17, 44 are your answers.
Answer:
$94.50
Step-by-step explanation:
3(50)=150 $1.50
4(40)=160 160(5)=800 $8.00
5(50)=250 250(10)=2500 $25.00
6(40)=240 240(25)=6000 $60.00
60+25+8+1.5=$94.50