The polynomial below is a perfect square trinomial of the form A^2-2AB+B^2. 9x^2-36x+16
1 answer:
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First, let's calculate the horizontal and vertical components of the wind speed (W) and the airplane speed (A), knowing that south is a bearing of 270° and northeast is a bearing of 45°:
Now, let's add the components of the same direction:
To find the resultant bearing (theta), we can use the formula below:
The angle -86° is equivalent to -86 + 360 = 274°.
Therefore the correct option is b.