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nikitadnepr [17]
4 years ago
13

An echo repeats two syllables.If the velocity of sound is 330 m/s , then the distance of the reflecting surface is-

Physics
1 answer:
Andreas93 [3]4 years ago
6 0
<span>Well, the main point you should remember is that we only can hear  20hz that leads to T=0.05sec which means that the distance leads us to velocity x time.
When calculating, you get 330 * 0.05=16.5 .
The number which you got from the previous step has to me multiplied 4 times (4 minutes) and you will get the answer you need - </span><span>a) 66.0 m.
Do hope it will help you! Regards!</span>
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Answer:

27 blocks

Explanation:

First, the expression to use here is the following:

P = F/A

Where:

P: pressure

F: Force exerted

A: Area of the block.

Now , we need to know the number of blocks needed to exert a pressure that equals at least 2 atm. To know this, we should rewrite the equation. We know that certain number of blocks, with the same weight and dimensions are putting one after one over the first block, so we can say that:

P = W/A

P = n * W1 / A

n would be the number of blocks, and W1 the weight of the block.We have all the data, and we need to calculate the area of the block which is:

A = 0.2 * 0.1 = 0.02 m²

Solving now for n:

n = P * A / W1

The pressure has to be expressed in N/m²

P = 2 atm * 1.01x10^5 N/m² atm = 2.02x10^5 N/m²

Finally, replacing all data we have:

n = 2.02x10^5 * 0.02 / 150

n = 26.93

We can round this result to 27. So the minimum number of blocks is 27.

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PE equals KE when KE is 50%. 

Like below:

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Remember, both KE and PE always have to add up to 100 so that is why PE is equal to KE when KE is 50% of energy. 

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