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lions [1.4K]
3 years ago
13

Sound waves cannot carry energy through. A water B air C a mirror D a vacuum

Physics
1 answer:
Ber [7]3 years ago
3 0
I looked up the question and got D- a vacuum
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Alpha radiation is ______.
KonstantinChe [14]
B because alpha radiation is just the amount of alpha particles, c could also be plausible but i think gamma rays are more deadly
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3 years ago
Two​ high-speed ferries leave at the same time from a city to go to the same island. The first​ ferry, the​ Cat, travels a
kumpel [21]

Answer:

1 hour

Explanation:

Since the definition of velocity is v=x/t, we can calculate the position at time t of an object moving at speed v with x=vt.

The position of the first ferry is x_1=v_1t

The position of the second ferry is x_2=v_2t

We want to know when they will be 6 miles apart. This means, if we call that distance d, that we want to know when the difference between their positions will be d, or x_1-x_2=d (we know that at the beginning the position of the ferry 1 is of higher value than that of ferry 2 since it left before).

We use our previous formulas then:

d=x_1-x_2=v_1t-v_2t=(v_1-v_2)t

Since we want the time, we do:

t=\frac{d}{v_1-v_2}

And substitute our values:

t=\frac{6\ miles}{30\ miles/hour-24\ miles/hour}=\frac{6\ miles}{6\ miles/hour} =1\ hour

7 0
3 years ago
A gamma ray with an energy of 3.40 × 10-14 joules strikes a photographic plate. We know that Planck's constant is 6.63 × 10-34 j
suter [353]
The correct answer is: "A. 5.13 x 10^19 hertz"
4 0
4 years ago
Read 2 more answers
What is the main function of an earthworm organ
Annette [7]

Answer:

brain

Explanation:

brain and blood

7 0
3 years ago
2. A 2000 kg car with speed 12.0 m/s hits a tree. The tree does not move or
krek1111 [17]

a) The work done by the tree is -1.44\cdot 10^5 J

b) The amount of force applied is 2880 N

Explanation:

a)

According to the work-energy theorem, the work done on the car is equal to the change in kinetic energy of the car. Therefore, we can write:

W=K_f - K_i = \frac{1}{2}mv^2 - \frac{1}{2}mu^2

where

W is the work done on the car

m is the mass of the car

u is its initial speed

v is its final speed

For the car in this problem, we have:

m = 2000 kg

u = 12.0 m/s

v = 0 (since the car comes to a stop, after the crash)

Therefore, the work done by the tree on the car is:

W=0-\frac{1}{2}(2000)(12.0)^2=-1.44\cdot 10^5 J

The work is negative because it is done in the direction opposite to the direction of motion of the car.

b)

The work done by the tree on the car can also be rewritten as

W=Fd

where

F is the force applied on the car

d is the displacement of the car during the collision

In this situation, we have:

W=-1.44\cdot 10^5 J is the work done

d=50.0 cm = 0.50 m is the displacement of the car during the collision

Solving the equation for F, we find the force exerted by the tree on the car:

F=\frac{W}{d}=\frac{-1.44\cdot 10^5 J}{0.50}=-2880 N

Where the negative sign means the force is applied opposite to the direction of motion of the car. Therefore, the magnitude of the force applied is 2880 N.

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

3 0
4 years ago
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