Given:
m(ar XW) = 47.3°
To find:
The measure of arc WVY
Solution:
In the given figure XW and XY are equal arcs.
m(ar XY) = m(ar XW)
m(ar XY) = 47.3°
Measure of complete circle = 360°
m(ar WVY) + m(ar YX) + m(ar XW) = 360°
m(ar WVY) + 47.3° + 47.3° = 360°
m(ar WVY) + 47.3° + 47.3° = 360°
m(ar WVY) + 94.6° = 360°
Subtract 94.6° from both sides.
m(ar WVY) + 94.6° - 94.6° = 360° - 94.6°
m(ar WVY) = 265.4°
The measure of arc WVY is 265.4°.
Answer:
Step-by-step explanation:
v = {[(20sin36°)i + (20cos36°)j] + 10i} mi/h
vE = 20sin36º + 10 = 21.76 mi/h
vN = 20cos36° = 16.18 mi/h
v = √(vE2 + vN2) = √(21.762 + 16.182) mi/h = 27.12 mi/h
θ = tan-1(vN/vE) = tan-1(16.18/21.76) = 36.6º north of east
Answer:
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Step-by-step explanation:
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Answer: Use the coordinates (0,-7)
Step-by-step explanation:
Answer:
B) Y = 5x - 10
Step-by-step explanation:
m = y2-y1 / x2-x1
Hope this helps. Pls give brainliest.