1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
klasskru [66]
4 years ago
12

Question is in the picture Thanks in Advance

Mathematics
2 answers:
djyliett [7]4 years ago
8 0

For this question, we can use the same side interior angle theorem.

Angles 1 and 2 are same side interior angles, which means that they are the interior angles on the same side.

To find the angle measure of the angles, we can plug in the value we have.

A=6x+18

A=6(10)+18

A=60+18

A=78

B=9x+12

B=9(10)+12

B=90+12

B=102

To find if the oars are parallel, we can use the same side interior angle theorem, which states that if the same side interior angles are supplementary, the lines are parallel.

78+102=180

Seeing as the angles are supplementary, the oars are parallel to each other.

Hope this helps.

頑張って!

olganol [36]4 years ago
3 0

Answer:

ffffffffffffffffffff

Step-by-step explanation:

You might be interested in
What is the logarithmic form of 144=12^2
Aloiza [94]
I beleive 144=2 is the answer.

If you have to divide that to get 1 number it would be 72.


???????????????????????
5 0
3 years ago
Read 2 more answers
Two trains leave stations 374 miles apart at the same time and travel toward each other. One train travels at 95 miles per hour
sveta [45]

2 hrs and 12 min or 2.2 hrs

5 0
3 years ago
The measure of an interior angle of a regular polygon is 120°. What is the measure of each exterior angle? The polygon has how m
Sunny_sXe [5.5K]

Answer:

60°, arms 6

Step-by-step explanation:

let the total arms = n

total generated angles in a regular polygon is = (n-2)×180

now,

(n-2)×180 = 120 n

or, 180n - 360 =120n

or, 60n = 360

or, n = 6

4 0
2 years ago
You’ve observed the following returns on Crash-n-Burn Computer’s stock over the past five years: 14 percent, –9 percent, 16 perc
MatroZZZ [7]

Answer:

a. 9%

b. 0.01445

c. 12.02%

Step-by-step explanation:

n = 5 years

Return rates = 14%, –9%, 16%, 21%, and 3%

a. Arithmetic average return

A= \frac{14-9+16+21+3}{5} \\A=9.00

b. Historical variance (to 5 decimal places)

V= \frac{\sum (X_i-A)^2}{n-1} \\V= \frac{(0.14-0.09)^2+(-0.09-0.09)^2+(0.16-0.09)^2(0.21-0.09)^2(0.03-0.09)^2}{5-1}\\ V=0.01445

c. Standard deviation.

s = \sqrt{V} \\s= \sqrt{0.01445}\\s=0.1202 = 12.02\%

8 0
3 years ago
1/4(1/3k+9)=6 step 1- 1/3k=15 step 2- 1/3k=15 step 3- k=5 find Olgas mistake step 1 step 2 steps 3 Olga did not make a mistake
shtirl [24]

Answer:

Step 3 contains error.

Step-by-step explanation:

The given equation is :

\dfrac{1}{4}(\dfrac{1}{3}k+9)=6

Step 1.

Cross multiplying,

(\dfrac{1}{3}k+9)=24

Step 2.

Subtract 9 from both sides

\dfrac{1}{3}k+9-9=24-9\\\\\dfrac{1}{3}k=15

Step 3.

Cross multiplying

k=15\times 3\\\\k=45

So, there is an error in step 3. The correct answer should be 45.

3 0
3 years ago
Other questions:
  • A vendor buys milk at a certain price, adds water and sells the adulterated milk at the same rate as he bought it for. He makes
    8·1 answer
  • Find the non permissible replacement for b in this expression b-1/b-1
    7·1 answer
  • Can you help me with my expanded notation please
    5·1 answer
  • What does x equal in this question
    5·1 answer
  • If Olivia traveled 70 miles in 2.5 hours, how many miles will Olivia travel in 9.5 hours at the same constant speed?
    15·2 answers
  • Which postulate or theorem proves that △ABC and △CDA are congruent?
    12·2 answers
  • Which of the following values are solutions to the inequality 1 + 5x < 4?
    8·1 answer
  • Ben has twenty-six coins in her pocket are all dollars(1$ coins) and quarters, and they add up to seventeen dollars in value. Ho
    7·1 answer
  • Someone please help. It is easy
    15·1 answer
  • Name:
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!