3 years ago

Need help asap!

1 answer:

6 0

Answers

1. Solve inside bracket first

7x^2+4x-26+7x^2+3x-15

= (14x^2+7x-41) Answer

2. 5x(6x^2+3x+7)-1(6x^2+3x+7)
= 30x^3+15x^2+35x-6x^2-3x-7
= (30x^3+9x^2+32x-7) Answer

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Find the missing side lengths. Leave your answers as radicals in simplest form. Please help!! Due today

Nataly_w [17]

Answer:

$m = 10\sqrt 3$

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Step-by-step explanation:

Required

Find m and n

Considering the given angle, we have:

$\sin(60) = \frac{Opposite}{Hypotenuse}$

This gives:

$\sin(60) = \frac{m}{20}$

Make m ths subject

$m = 20 * \sin(60)$

$\sin(60) =\frac{\sqrt 3}{2}$

So, we have:

$m = 20 *\frac{\sqrt 3}{2}$

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Considering the given angle again, we have:

$\cos(60) = \frac{Adjacent}{Hypotenuse}$

This gives:

$\cos(60) = \frac{n}{20}$

Make n the subject

$n = 20 * \cos(60)$

$\sin(60) =\frac{1}{2}$

So, we have:

$n = 20 *\frac{1}{2}$

$n = 10$

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Step-by-step explanation:

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3 years ago

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