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Answer:
is standard equation of hyperbola with vertices at (0, ±9) and foci at (0, ±11).
Step-by-step explanation:
We have given the vertices at (0, ±9) and foci at (0, ±11).
Let (0,±a) = (0,±9) and (0,±c) = (0,±11)
The standard equation of parabola is:
From statement, a = 9
c² = a²+b²
(11)² = (9)²+b²
121-81 = b²
40 = b²
Putting the value of a² and b² in standard equation of parabola, we have
which is the answer.
12. 
r - 3 = 4(-5)
r - 3 = -20
r = -20 + 3
r = -17
13.
6(r - 2) = -7(5)
6r - 12 = -35
6r = -35 + 12
6r = - 23
r =
r - 3 = 4(-5)
r - 3 = -20
r = -20 + 3
r = -17
13.
6(r - 2) = -7(5)
6r - 12 = -35
6r = -35 + 12
6r = - 23
r =