All categories

2 years ago

A dvd case is 9/16 thick. how many of these cases will fit on a shelf that is 1 1/2 ft wide.

Mathematics

1 answer:

SVETLANKA909090 [29]2 years ago

5 0

11/2 * 16/9

11/1 * 8/9

88/9

You might be interested in

Simplify the variable expression by evaluating it's numerical part m-13+42-6

goldfiish [28.3K]

ANSWER

$m + 23$

EXPLANATION

The given expression is

$m - 13 + 42 - 6$

We regroup the numerical parts to get;

$m + 42 - 6 - 13$

Now let us simplify the negative numbers.

$m + 42 - 19$

We now subtract 19 from 42 to get;

$m + 23$

We can't simplify further

Hence the simplest form is:

$m + 23$

3 0

3 years ago

A car with a mass of 1,250 kg travels at 2.24 m/s and bumps into a stopped car with a mass of 1,300 kg. After the collision, the

ddd [48]

Answer:

0.57 m/s

Step-by-step explanation:

4 0

3 years ago

What would be the first step to solve for n in the equation 3n-7=30?

taurus [48]

The first step would be to add 7 to both sides.
3n-7=30
add 7
3n=37
divide by 3
n=12.33

4 0

2 years ago

Read 2 more answers

Find the total number of outcomes when choosing a flavor of ice cream. ( Vanilla, strawberry, chocolate, butterscotch) a topping

Doss [256]

Answer:

Step-by-step explanation:

4 flavors

2 toppings

2 containers

4x 2= 8

8x2=16

7 0

2 years ago

Read 2 more answers

In an effort to estimate the mean of amount spent per customer for dinner at a major Lawrence restaurant, data were collected fo

larisa86 [58]

Answer:

The 99% confidence interval for the population mean is 22.96 to 26.64

Step-by-step explanation:

Consider the provided information,

A sample of 49 customers. Assume a population standard deviation of $5. If the sample mean is $24.80,

The confidence interval if 99%.

Thus, 1-α=0.99

α=0.01

Now we need to determine $z_{\frac{\alpha}{2}}=z_{0.005}$

Now by using z score table we find that $z_{\frac{\alpha}{2}}=2.58$

The boundaries of the confidence interval are:

$\mu-z_{\frac{\alpha}{2}}\times \frac{\sigma}{\sqrt{n} }\\24.80-2.58\times \frac{5}{\sqrt{49}}=22.96\\\mu+z_{\frac{\alpha}{2}}\times \frac{\sigma}{\sqrt{n} }\\24.80+2.58\times \frac{5}{\sqrt{49}}=26.64$

Hence, the 99% confidence interval for the population mean is 22.96 to 26.64

3 0

3 years ago