Volume of reg sq. pyramid = vp vp = 1/3×s^2×h, where s = side and h = height Volume of cone = vc =1/3×h×pi×r^2 Now we know that h is the same for both, and the cones diameter = s of square base, so radius (r) = 1/2 s so now vc = 1/3×h×pi×(1/2s)^2 let's remove the same items for both vc and vp so 1/3 and h now let's plug an arbitrary number into each: vc = pi (10/2)^2 = 3.14×25 = 78.54 vp = s^2 = 10^2 = 100 So any square pyramid has slightly more volume than the cone
