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Vinil7 [7]
3 years ago
14

Please help on the fraction question!

Mathematics
2 answers:
Natasha2012 [34]3 years ago
8 0
(6 x 5) / 9 = 3.33333333 


Contact [7]3 years ago
8 0
You multiply by the recipricol... its 6*9 then divide by 5 so the answer is 54/5 or 10.8
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3 years ago
Need help on these math questions. please and thank u
Svetach [21]

9514 1404 393

Answer:

  a) x = -3

  b) y = (28/27)x -27

Step-by-step explanation:

a) College street has a slope of 0, so is a horizontal line. 2nd Ave is perpendicular, so is a vertical line, described by an equation of the form ...

  x = constant

For 2nd Ave to intersect the point (-3, 1), the constant must match that x-coordinate. The equation is ...

  x = -3

__

b) Since Ace Rd is perpendicular to Davidson St, its slope will be the opposite reciprocal of the slope of Davidson St. The slope of Ace Rd is ...

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Using the point-slope equation for a line, we can model Ace Rd as ...

  y -y1 = m(x -x1)

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4 0
3 years ago
Evaluate lim x approaches to 2 : (sqrt(6-x)-2)/(sqrt(3-x)-1)
solong [7]

Answer:

The answer is "0.5".

Step-by-step explanation:

Given:

\to \lim_{x\to 2}  \frac{(\sqrt{(6-x)}-2)}{(\sqrt{(3-x)}-1)}\\\\ \to \lim_{x\to 2}  \frac{\frac{d(\sqrt{(6-x)}-2)}{dx}}{\frac{(\sqrt{(3-x)}-1)}{dx}}\\\\

\to \lim_{x\to 2} \frac{\frac{-1}{2\sqrt{(6-x)} }}{\frac{-1}{2\sqrt{(3-x)}}}\\\\

\to \lim_{x\to 2} \frac{\sqrt{3-x}}{\sqrt{6-x}}\\\\ \to \frac{\sqrt{3-2}}{\sqrt{6-2}}\\\\ \to \frac{\sqrt{1}} {\sqrt{4}}\\\\ \to \frac{1}{2}\\\\ \to 0.5

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3 years ago
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Cloud [144]
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3 years ago
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Fittoniya [83]

Answer:

True

Step-by-step explanation:

Think about it. you are cutting a rectangle in half. and when you put it in dimensions its still the same thing!

8 0
3 years ago
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