Answer:
4.88
Step-by-step explanation:
sinA=opposite/adjacent
sin24=x/12
12(0.40673664307)=x
x=4.88083971691
Answer:
a) 8.13
b) 4.10
Step-by-step explanation:
Given the rate of reaction R'(t) = 2/t+1 + 1/√t+1
In order to get the total reaction R(t) to the drugs at this times, we need to first integrate the given function to get R(t)
On integrating R'(t)
∫ (2/t+1 + 1/√t+1)dt
In integration, k∫f'(x)/f(x) dx = 1/k ln(fx)+C where k is any constant.
∫ (2/t+1 + 1/√t+1)dt
= ∫ (2/t+1)dt+ ∫ (1/√t+1)dt
= 2∫ 1/t+1 dt +∫1/+(t+1)^1/2 dt
= 2ln(t+1) + 2(t+1)^1/2 + C
= 2ln(t+1) + 2√(t+1) + C
a) For total reactions from t = 1 to t = 12
When t = 1
R(1) = 2ln2 + 2√2
≈ 4.21
When t = 12
R(12) = 2ln13 + 2√13
≈ 12.34
R(12) - R(1) ≈ 12.34-4.21
≈ 8.13
Total reactions to the drugs over the period from t = 1 to t= 12 is approx 8.13.
b) For total reactions from t = 12 to t = 24
When t = 12
R(12) = 2ln13 + 2√13
≈ 12.34
When t = 24
R(24) = 2ln25 + 2√25
≈ 16.44
R(12) - R(1) ≈ 16.44-12.34
≈ 4.10
Total reactions to the drugs over the period from t = 12 to t= 24 is approx 4.10
I think it’s 3 not sure tho because i forgot most things about it
Y = x + 5A linear equation (in slope-intercept form) for a line perpendicular to y = -x + 12 with a y-intercept of 5.y = 1/2x - 5Convert the equation 4x - 8y = 40 into slope-intercept form.y = -1/2x + 5A linear equation (in slope-intercept form) which is parallel to x + 2y = 12 and has a y-intercept of 5.3x - y = -5A linear equation (in standard form) which is parallel to the line containing (3, 5) and (7, 17) and has a y-intercept of 5.y = -3x + 1A linear equation (in slope-intercept form) which contains the points (10, 29) and (-2, -7).y = -5A linear equation which goes through (6, -5) and (-12, -5).x = -5A linear equation which is perpendicular to y = 12 and goes through (-5, 5).y = 5A linear equation which is parallel to y = 12 and goes through (-5, 5).y = -x + 5A linear equation (in slope-intercept form) which is perpendicular to y = x and goes through (3, 2).y = -5xA linear equation (in slope-intercept form) which goes through the origin and (1, -5).x = 2A linear equation which has undefined slope and goes through (2, 3).y = 3A linear equation which has a slope of 0 and goes through (2, 3).2x + y = -9A linear equation (in standard form) for a line with slope of -2 and goes through point (-1, -7).3x +2y = 1A linear equation (in standard form) for a line which is parallel to 3x + 2y = 10 and goes through (3, -4).y + 4 = 3/2 (x - 3)A linear equation (in point-slope form) for a line which is perpendicular to y = -2/3 x + 9 and goes through (3, -4).y - 8 = -0.2(x + 10)<span>The table represents a linear equation.
Which equation shows how (-10, 8) can be used to write the equation of this line in point-slope form?</span>
