Transmission electron magnifying lens - The transmission electron magnifying instrument utilizes electrons rather than light. a light magnifying lens is constrained by the wavelength of light. TEMs utilize electrons as "light source" and their much lower wavelength makes it conceivable to get a determination a thousand times superior to with a light magnifying lens. The likelihood for high amplifications has made the TEM a significant instrument in both medicinal, natural and materials research.Compound light magnifying instrument - Microscope with more than one focal point and its own particular light source. There are visual focal points in the bonicular eyepieces and target focal points in a turning nosepiece nearer to the example. To determine the energy of amplification of a compund light magnifying instrument, it's expected to take the energy of the target focal point and duplicate it by the eyepiece which is by and large 10x. Albeit at times found as monocular with one visual focal point, the compound binocular magnifying lens is all the more regularly utilized today. The principal light magnifying lens goes back to 1595, when Zacharias Jansen made a compound magnifying instrument that utilized crumbling tubes and delivered amplifications up to 9X.
There are often not more than one or two independent variables tested in an experiment, otherwise it is difficult to determine the influence of each upon the final results. There may be several dependent variables, because manipulating the independent variable can influence many different things.
Answer:
Explanation:
Sensory receptor interact with stimuli, such as light sound temperature and pain which is transformed into the code that is carried to the brain by the chain of neurons. Once the signal reaches the end of an axon, which is at the end of neuron, a neurotransmitter is released and the process repeats.
Answer: A = 154 m²
Explanation: First solve for radius r
Using circumference formula
C= 2πr
Derive to find r:
r = C / 2π
= 44 m / 2 ( 3.14 )
= 7 m²
Solve for area
A = π r²
= ( 3.14 ) ( 7 m )²
= 154 m²
1. Ee
2. Ee
3. ee
4. ee
5. e
6. e
7. E
8. e
9. 2:2 or 50% Rr 50% rr
10. 2:2 or 50% Heterozygous unattached earlobes 50% homozygous attached earlobes
