These are the steps:
1. Find the area of the trapezium {Whole figure).
2. FInd the area of the rectangle (unshaded).
3. Area of the shaded = Area of trapezium - Area of the rectangle.
<u>Step 1: Find the area of the trapezium</u>:
Formula : Area of trapezium = 1/2 (a + b)h
Area = 1/2 ( 25 + 15) (12) = 240 yd²
<u>Step </u><u>2 :</u><u> Find the area of the rectangle</u>:
Formula : Area = Length x Width
Area = 12 x 3 = 36 yd²
<u>Step 3: Find the shaded region:</u>
240 - 36 = 204 yd²
Answer: 204 yd²
Answer:
k = 6 : 5 : 4
Step-by-step explanation:
BC : AB : AC = 18 : 15 : 12 = 6 : 5 : 4
EF : DE : DF = 12 : 10 : 8 = 6 : 5 : 4
Answer:
36 in over 2
Step-by-step explanation:
the large bag is 5/6 lb, the smaller bags will be 1/3 lb, so it should be 5/6 ÷ 1/3
![\bf \cfrac{5}{6}\div \cfrac{1}{3}\implies \cfrac{5}{\underset{2}{~~\begin{matrix} 6 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\cdot \cfrac{~~\begin{matrix} 3 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{1}\implies \cfrac{5}{2}\implies 2\frac{1}{2}](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B5%7D%7B6%7D%5Cdiv%20%5Ccfrac%7B1%7D%7B3%7D%5Cimplies%20%5Ccfrac%7B5%7D%7B%5Cunderset%7B2%7D%7B~~%5Cbegin%7Bmatrix%7D%206%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%7D%7D%5Ccdot%20%5Ccfrac%7B~~%5Cbegin%7Bmatrix%7D%203%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%7D%7B1%7D%5Cimplies%20%5Ccfrac%7B5%7D%7B2%7D%5Cimplies%202%5Cfrac%7B1%7D%7B2%7D)
Hey!
Okay, to solve this problem, we'd first have to multiply both sides by two. The reason we do this is to get

on its own.
<em>Original Equation : </em>

<
<em>New Equation {Changed by Multiplying 2 on Both Sides} :</em>

<

(

)
And we simplify the equation to get our answer.
<em>Old Equation :</em>

<

(

)
<em>New Equation {Changed by Simplification} :</em>
y < -6
<em>So, the equation

< -3 simplified is</em>
y < -6.
Hope this helps!
- Lindsey Frazier ♥