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2 years ago

Graph the function. y = 7(6)x+2 + 1

Mathematics

1 answer:

Crazy boy [7]2 years ago

7 0

Answer:

Step-by-step explanation:

I must assume that you meant y = 7(6)^(x+2) + 1.

Please use " ^ " to indicate exponentiation. Thanks.

1) Graph y = 6^x first. Its y-intercept is (0, 1). It has a horizontal asymptote in y = 0. The graph starts in Quadrant II and progresses into Quadrant I, never touching or crossing the x-axis.

2) Stretch your graph vertically by a factor of 7.

3) Translate your resulting graph up by 1 unit.

4) Translate your graph 2 units to the LEFT.

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<h2>Answer:</h2>

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<h2>Explanation:</h2>

Hello! Remember you have to write complete questions in order to get good and exact answers. Here I'll assume the diagram shown below. In that figure, we know that:

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