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3 years ago

Graph the function. y = 7(6)x+2 + 1

Mathematics

1 answer:

Crazy boy [7]3 years ago

7 0

Answer:

Step-by-step explanation:

I must assume that you meant y = 7(6)^(x+2) + 1.

Please use " ^ " to indicate exponentiation. Thanks.

1) Graph y = 6^x first. Its y-intercept is (0, 1). It has a horizontal asymptote in y = 0. The graph starts in Quadrant II and progresses into Quadrant I, never touching or crossing the x-axis.

2) Stretch your graph vertically by a factor of 7.

3) Translate your resulting graph up by 1 unit.

4) Translate your graph 2 units to the LEFT.

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Which of these is the standard form of the following function?<br> f(n) = 7(7 - 1)2 + 3

mina [271]

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3 years ago

I need help on this.

mote1985 [20]

Let's go:

7 = x

38 + x = 180

x = 180 - 38

x = 142°

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I hope I helped you

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4 years ago

Find the absolute value of 2 and 2 3rd and negative 9 over 4

gayaneshka [121]

we are given

absolute value of 2 and 2 3rd and negative 9 over 4

Firstly , we need write it in terms of expression

2 and 2 3rd is

$2+\frac{2}{3}$

so, we get as

$|2+\frac{2}{3} -\frac{9}{4} |$

now, we can simplify it

Firstly , we will find common denominator

$|\frac{2*12}{1*12} +\frac{2*4}{3*4} -\frac{9*3}{4*3} |$

$|\frac{24}{12} +\frac{8}{12} -\frac{27}{12} |$

we can see that

all denominators are same

so, we can combine numerators

$=|\frac{24+8-27}{12} |$

$=|\frac{5}{12} |$

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