Question

Graph the function. y = 7(6)x+2 + 1

Answer 1

Answer:

Step-by-step explanation:

I must assume that you meant   y = 7(6)^(x+2)  + 1.

Please use " ^ " to indicate exponentiation.  Thanks.

1) Graph y = 6^x first.  Its y-intercept is (0, 1).  It has a horizontal asymptote in y = 0.  The graph starts in Quadrant II and progresses into Quadrant I, never touching or crossing the x-axis.

2) Stretch your graph vertically by a factor of 7.

3) Translate your resulting graph up by 1 unit.

4)  Translate your graph 2 units to the LEFT.