Factor completely 2x2 − 18. Prime 2(x2 − 9) 2(x 3)(x − 3) 2(x 3)(x 3).

Mathematics

1 answer:

Law Incorporation [45]2 years ago

6 0

By using identity we got the factorization form of $2x^2-18$ as

$2(x-3)(x+3)$

<h3>What is factorization?</h3>

factorization is a way of writing any expression in form of product of some expressions

Given polynomial

$2x^2-18$

We can factorize it as

$2x^2-18\\\\2(x^2-9)\\\\2(x^2-3^2)\\\\2(x-3)(x+3)$

By using identity we got the factorization form of $2x^2-18$ as

$2(x-3)(x+3)$

To learn more about factorization visit :brainly.com/question/25829061

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The jogging track is of a mile long. If Ashley jogged around it 4 times, how far did she run?

matrenka [14]

Answer: 4 miles

Step-by-step explanation:

If Ashley ran 1 mile 4 times, she ran 1+1+1+1, or 1*4, or 4 miles.

Hope it helps <3

5 0

3 years ago

Determine the equation of the polynomial, p(x),in both factored and standard form.

melamori03 [73]

We can see that the graph touches $x=-1$ without crossing the x-axis (i.e. it is a double solution), and then there's another zero at $x=2$ (this time it's a crossing zero, so a single solution).

This leads, up to multiple, to the polynomial

$p(x)=a(x+1)^2(x-2)$

If we impose the passing through $(0,4)$ we have

$p(0)=4=a(1)(-2) \iff -2a=4 \iff a=-2$

So, the polynomial is

$p(x)=-2(x+1)^2(x-2)=-2 x^3 + 6 x + 4$

Finally, to solve $p(x)$ , simply look at the graph, searching for the points, where the graph is below the x-axis. You can see that this happens only if $x>2$ , so that's the solution to your question.