Hello,
A=(-4,2)
B=(3,-5)
AB≡y-2=(x+4)(-7)/7==>y=-x-2
Slope of the perpendicular: 1
y-2=(x-1)1==>y=x+1 is the equation of the perpendicular.
Intersection: y=x+1 and y=-x-2 ==>(-3/2,-1/2)=Q
|PQ|²=(-1/2-2)²+(1+3/2)²=25/2
|PQ|=5√2/2≈3.5355339059....
domain represents the x values so for example in a diagonal line that continues infinitely, the domain is all real numbers or (-infinity, infinity)
range represents y values so it would also be all real numbers or (-infinity, infinity)
let’s say there is a line (refer to pic) that moves ONLY from point (-3, -1) and (2, 2)
the domain would be [-3, 2]
we use brackets because it’s a real number unlike infinity (also because it’s a closed circle on the graph; if the graph had an open circle you would use a parenthesis)
and the range would be [-1, 2]
if you have any more questions about this explanation feel free to ask!
Answer:
y = -2x + 5
Step-by-step explanation:
Slope-intercept form: y = mx + b
The slope of the line, m, is -2 because the line shows a negative trend and moves right 1 unit every time a point moves down 2 units.
The y-intercept, b, is 5 because the line crosses that number once on the y-axis.
3(25x^3-16)
Hope that is what you were looking for