We havep(X)=eβ0+β1X1+eβ0+β1X⇔eβ0+β1X(1−p(X))=p(X),p(X)=eβ0+β1X1+eβ0+β1X⇔eβ0+β1X(1−p(X))=p(X),which is equivalent top(X)1−p(X)=eβ0+β1X.p(X)1−p(X)=eβ0+β1X.
To use the Bayes classifier, we have to find the class (kk) for whichpk(x)=πk(1/2π−−√σ)e−(1/2σ2)(x−μk)2∑Kl=1πl(1/2π−−√σ)e−(1/2σ2)(x−μl)2=πke−(1/2σ2)(x−μk)2∑Kl=1πle−(1/2σ2)(x−μl)2pk(x)=πk(1/2πσ)e−(1/2σ2)(x−μk)2∑l=1Kπl(1/2πσ)e−(1/2σ2)(x−μl)2=πke−(1/2σ2)(x−μk)2∑l=1Kπle−(1/2σ2)(x−μl)2is largest. As the log function is monotonally increasing, it is equivalent to finding kk for whichlogpk(x)=logπk−(1/2σ2)(x−μk)2−log∑l=1Kπle−(1/2σ2)(x−μl)2logpk(x)=logπk−(1/2σ2)(x−μk)2−log∑l=1Kπle−(1/2σ2)(x−μl)2is largest. As the last term is independant of kk, we may restrict ourselves in finding kk for whichlogπk−(1/2σ2)(x−μk)2=logπk−12σ2x2+μkσ2x−μ2k2σ2logπk−(1/2σ2)(x−μk)2=logπk−12σ2x2+μkσ2x−μk22σ2is largest. The term in x2x2 is independant of kk, so it remains to find kk for whichδk(x)=μkσ2x−μ2k2σ2+logπkδk(x)=μkσ2x−μk22σ2+logπkis largest.
ng expression
∫0.950.0510dx+∫0.050(100x+5)dx+∫10.95(105−100x)dx=9+0.375+0.375=9.75.∫0.050.9510dx+∫00.05(100x+5)dx+∫0.951(105−100x)dx=9+0.375+0.375=9.75.So we may conclude that, on average, the fraction of available observations we will use to make the prediction is 9.75%9.75%.res. So when p→∞p→∞, we havelimp→∞(9.75%)p=0.
The correct answer is X=-2.
First remove the parentheses and factor out 2.
1/2•(2-6x)-4(x+3/2)=-(x-3)+4 turns into
1/2•2(1-3x)-4(x+3/2)=-(x-3)+4.
Then distribute -4 through the parentheses,
1/2•2(1-3x)-4x-6=-(x-3)+4
Then change the sign of the x-3 to x+3,
1/2•2(1-3x)-4x-6=-x+3+4
Then reduce the numbers with the greatest common factor which is 2,
and remove unnecessary parentheses,
1-3x-4x-6=-x+7
Then calculate the differences and collect like terms,
-5-7x=-x+7
Then move the variable to the left side and change its sign, and move the constant to the right hand side and change its sign,
-7x+x=7+5
Then add and collect the like terms,
-6x=12
And finally divide both sides by -6 to get X=-2.
Whew lol
V=BH/3
V=(4)(6)/3
V=(24)/3
V=8
Answer:
YES
Step-by-step explanation:
So how you can figure this out is you do the Distributive Property.
So it will be 12x^3+12y^2+6y^2+6.
The next thing you have to do is add together the ones that are similar which is 12y^2+6y^2 to get 18y^2.
Your answer is 12x^3+18y^2+6. So YES it can be factored into that form.
Answer:
Question (1) is 5
Step-by-step explanation:
3x3=9
9+1=10
10
— = 5
2
