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3 years ago

Enter the equation of the circle described below. Center (-1, 4), radius = √3

Mathematics

1 answer:

lorasvet [3.4K]3 years ago

3 0

EQUATION OF A CIRCLE: (x-h)² + (y-k)² =r²

= (x+1)² + (y-4)² =3

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Find all x-values for which f ( x ) = 2 for the function below.

Angelina_Jolie [31]

Answer:

Step-by-step explanation:

First let us get the equation of the coordinates

y-y0 = m(x-x0)

Using the coordinates ( - 3, 2 ), ( - 1, 0 )

m = 0-2/-1-(-3)

m = -2/2

m = -1

Substitute m = -1 and (-1, 0) into the formula

y - 0 = -1(x+1)

y = -x-1

f(x) = -x-1

Since f(x) = 2

2 = -x-1

-x = 2+1

-x = 3

x = -3

Hence the value of x is -3

8 0

2 years ago

Help with some math homework? The area of a triangle is 110 square inches. the height of the triangle is 8 less than 3 times its

Alenkasestr [34]

A = h x b; where A = area of a triangle; h = height of the triangle; b = base of the riangle;
So, we have the equation : 110 = (3b - 8)b;
We solve the equation 3b^2 - 8b - 110 = 0;
The positiv solution is b = 7.53 cm;
h = 3 x 7.53 - 8;
h = 14.59 cm;

3 0

2 years ago

Can someone help me on number one plz. Help me by explaining the steps ;D

harina [27]

0+1=1
1-0=1
1x1=1
1/1=1
1 is in everything if this didnt help tell me

3 0

2 years ago

Read 2 more answers

What's the estimate for 2-9

andrew11 [14]

The estimate between 2 and 9 is 7

5 0

2 years ago

A survey was conducted that asked 1003 people how many books they had read in the past year. Results indicated that x overbar eq

Sergio [31]

Answer:

The 99% confidence interval would be given (11.448;14.152).

Step-by-step explanation:

1) Important concepts and notation

A confidence interval for a mean "gives us a range of plausible values for the population mean. If a confidence interval does not include a particular value, we can say that it is not likely that the particular value is the true population mean"

$s=16.6$ represent the sample deviation

$\bar X=12.8$ represent the sample mean

n =1003 is the sample size selected

Confidence =99% or 0.99

$\alpha=1-0.99=0.01$ represent the significance level.

2) Solution to the problem

The confidence interval for the mean would be given by this formula

$\bar X \pm z_{\alpha/2} \frac{s}{\sqrt{n}}$

We can use a z quantile instead of t since the sample size is large enough.

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

And replacing into the confidence interval formula we got:

$12.8 - 2.58 \frac{16.6}{\sqrt{1003}}=11.448$

$12.8 + 2.58 \frac{16.6}{\sqrt{1003}} =14.152$

And the 99% confidence interval would be given (11.448;14.152).

We are confident that about 11 to 14 are the number of books that the people had read on the last year on average, at 1% of significance.

3 0

3 years ago