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2 years ago

How do you simplify radical 144

1 answer:

8 0

√144 = 12

Broken down, 12*12 = 144. Roots = Radicals.

Since I can't explain, other examples are...
√4 = 2*2
√9 = 3*3
√16 = 4*4
√25 = 5*5
√36 = 6*6

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Jefferey Says he has 6.8 dollars. How to you write the decimal 6.8 when it refers to money? Explain.

Bogdan [553]

6 Dollars and 80 cents

8 0

2 years ago

Read 2 more answers

2x - 5y = 16 x - 2y = 5 elimination?

harina [27]

Answer:

Y = 6

X = 24

Step-by-step explanation:

2x -5y = 16

(x -2y =5)*2

_______________

2x -5y = 16

2x - 4y = 10

_______________

(2x -5y = 16) - (2x - 4y = 10)

_______________

0x -y = 6

_______________

y =6

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Replacing in equation 1:

2x - 5(6) = 16

so, 2x = 16 + 30

2x = 48

x = 24

6 0

3 years ago

2 factors of 36 add up to 15 What are they?

Margaret [11]

Hey there!!

What are the factors of 36?

Ans :- 1 , 36 , 2 , 18 , 3 , 12 , 4 , 9 , 6

Which of these numbers add up to 15 ?

... 12 + 3 = 15

The number are 15.

They add up to 15 and both of these are factors of 36.

Hope my answer helps!!

3 0

2 years ago

One bag contains 7 red chips and 4 yellow chips. Another bag contains 2 red chips and 8 yellow chips. A chip is drawn from each

IgorC [24]

Answer:

We have 11 chips in the first bag and 4 are yellow......so the probability of drawing a yellow

Step-by-step explanation:

4 0

3 years ago

What is the value of x to the nearest tenth??

Stolb23 [73]

Answer:

$\displaystyle 12,3 ≈ x$

Step-by-step explanation:

We have to determine which trigonometric ratio to use, depending on what is displayed for us, and we will be using the cotangent [or tangent] ratio, this time with two angle measures:

$\displaystyle cot\:39° = \frac{x}{10} → 10cot\:39° ≈ 12,34897157 ≈ 12,3 \\ \\ tan\:39° = \frac{10}{x} → \frac{10}{tan\:39°} ≈ 12,34897157 ≈ 12,3 \\ \\ \\ OR \\ \\ \\ cot\:51° = \frac{10}{x} → \frac{10}{cot\:51°} ≈ 12,34897157 ≈ 12,3 \\ \\ tan\:51° = \frac{x}{10} → 10tan\:51° ≈ 12,34897157 ≈ 12,3$

Extended Information on Trigonometric Ratios

$\displaystyle \frac{OPPOSITE}{HYPOTENUSE} = sin\:θ \\ \frac{ADJACENT}{HYPOTENUSE} = cos\:θ \\ \frac{OPPOSITE}{ADJACENT} = tan\:θ \\ \frac{HYPOTENUSE}{ADJACENT} = sec\:θ \\ \frac{HYPOTENUSE}{OPPOSITE} = csc\:θ \\ \frac{ADJACENT}{OPPOSITE} = cot\:θ$

I am joyous to assist you anytime.

3 0

3 years ago