Since the lengths of the segments AD=PD are equal that means that the triangle is an isosceles triangle. This also means that the angles A and P (in the triangle) are equal.
This also means that the angle P' (the one inside the quadrilateral) is equal to:
![180-\measuredangle B](https://tex.z-dn.net/?f=180-%5Cmeasuredangle%20B)
Now, if we extend the sides DP and CB we notice that the angles P' and Q
are equal
The only way that this angles can be equal is if the line segments DP and CB are parallel, this comes from the fact that two alternate interior angles are equal if and only if the lines are parallel.
Answer:
you left something out but you need to put it in a better understanding
Step-by-step explanation:
Answer:
0.25x - 4 > 6
Step-by-step explanation:
First, we would like to thank you for all of the additional support you offer at home. ... Subtract the absolute values. Multiply the denominators. 4. Reduce if necessary. 3. 10 x. 2. 3. 6. 30. = 1. 5. 3 ... 1 less than the product of 3 and m 3m – 1.
0.6*10m=6m 0.6*5n=3n rewrite 6m-3n
hope this helps have a nice nite