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Nuetrik [128]
4 years ago
5

Cody bought two burgers and two

Mathematics
1 answer:
8_murik_8 [283]4 years ago
7 0

Answer:

$5

Step-by-step explanation:

Let the cost of one burger be $b while the cost of one small fries be s

2 burgers and 2 small fries cost $14

This means that;

2b + 2s = 14

divide both sides by 2

b + s = 7 •••••••• (i)

Three burgers and four small fries cost $23

Mathematically;

3b + 4s = 23 •••••••• (ii)

From i , we can see that s = 7- b

we can now substitute this into equation ii

3b + 4(7-b) = 23

3b + 28 -4b = 23

4b -3b = 28 -23

b = $5

one burger costs $5

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Answer:

The percentage that of people who gave the movie a rating between 6.8 and 8.8

<em>P(6.8≤X≤8.8)  = 83.9≅ 84 percentage</em>

Step-by-step explanation:

<u> Step(i):-</u>

Mean of the Population = 8.3 points

Standard deviation of the Population = 0.5 points

Let 'X' be the random variable in normal distribution

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Z = \frac{x-mean}{S.D} = \frac{6.8-8.3}{0.5} = -3

Let X = 8.8

Z = \frac{x-mean}{S.D} = \frac{8.8-8.3}{0.5} = 1

The probability that of people who gave the movie a rating between 6.8 and 8.8

<em>P(6.8≤X≤8.8) = P(-3≤Z≤1)</em>

                     = P(Z≤1)- P(Z≤-3)

                    =  0.5 + A(1) - ( 0.5 -A(-3))

                   = A(1) + A(3)       (∵A(-3)=A(3)

                  =  0.3413 +0.4986    (∵ From Normal table)

                 = 0.8399

<u><em>Conclusion:-</em></u>

The percentage that of people who gave the movie a rating between 6.8 and 8.8

<em>P(6.8≤X≤8.8)  = 83.9≅ 84 percentage</em>

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