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2 years ago

Someone help me multiple choice!!! questions 1-5!!!

Mathematics

1 answer:

lesantik [10]2 years ago

7 0

Answer:B,C,A,C.

Step-by-step explanation:

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Help me with this please

SCORPION-xisa [38]

Answer:

what grade is that 4

Step-by-step explanation:

8 0

3 years ago

Ophia earned $2,000 last month. She used 35 of her earnings to pay her bills. With the remaining money, she bought two shirts fo

Andrej [43]

Sophia has $ 1912.03 left from last month's earnings

Solution:

Given, sophia earned $2,000 last month.

She used 35 of her earnings to pay her bills.

With the remaining money, she bought two shirts for $19.99 each and a pair of earrings for $12.99.

We have to find how much money does Sophia have left from last month's earnings

Now, we know that,

Left money = earned money – used money

= 2000 – (bills paid + 2 shirts cost + 1 pair of ear rings)

= 2000 – (35 + 2 x 19.99 + 12.99)

= 2000 – (35 + 39.98 + 12.99)

= 2000 – (87.97) = 1912.03

Hence, Sophia has $ 1912.03 left with her.

5 0

4 years ago

Which inequality has -25 in its solution set?

Anastaziya [24]

Answer:

The answer is Y+20> -30

Step-by-step explanation:

I took the test

4 0

3 years ago

Imagine it is your new friend's first day in Pre-Calculus class. What types of prior knowledge about Calculus will he or she nee

tino4ka555 [31]

Prior knowledge about precalculus or calculus?

Precalculus comes before calculus 1.

Are you looking for knowledge prior to precalculus or before calculus 1?

7 0

3 years ago

Read 2 more answers

A statistics professor receives an average of five e-mail messages per day from students. Assume the number of messages approxim

kaheart [24]

Answer:

The probability that on a randomly selected day the statistics professor will have five messages is 0.1755.

Step-by-step explanation:

Let the random variable X represent the number of e-mail messages per day a statistics professor receives from students.

The random variable is approximated by the Poisson Distribution with parameter λ = 5.

The probability mass function of X is as follows:

$P(X=x)=\frac{e^{-5}\cdot 5^{x}}{x!};\ x=0,1,2,3...$

Compute the probability that on a randomly selected day she will have five messages as follows:

$P(X=5)=\frac{e^{-5}\cdot 5^{5}}{5!}$

$=\frac{0.006738\times 3125}{120}\\\\=0.17546875\\\\\approx 0.1755$

Thus, the probability that on a randomly selected day the statistics professor will have five messages is 0.1755.

7 0

4 years ago