If they were 19& people at the pool what is the percentage 16.9
Ab+ac=a(b+c) where a is the greatest common factor
find greatest common factor of 10 and 50
10=1,2,5,10
50=1,2,5,10,25,50
greatest common is 10
a=10
10(1)+10(5)=10(1+5)=10(6)=60
Answer:
hi so read explanation
Step-by-step explanation:
four sixteenth notes
Four eighth notes equal one- half note in duration and eight eighth notes equal one whole note. Two sixteenth notes are to equal one- eighth note in duration and four sixte enth notes equal one- quarter note in durations. hope dis helped
Answer:
3.14159, this is π
Followed by 2-6-5-3-5-8-9
Circumference over diameter
7-9, then 3-2-3
OMG! Can't you see?
8-4-6-2-6-4-3
And now we're on a spree
38 and 32, now we're blue
Oh, who knew?
7, 950 and then a two
88 and 41, so much fun
Now a run
9-7-1-6-9-3-9-9
Then 3-7, 51
Half way done!
0-5-8, now don't be late
2-0-9, where's the wine?
7-4, it's on the floor
Then 9-4-4-5-9
2-3-0, we gotta go
7-8, we can't wait
1-6-4-0-6-2-8
We're almost near the end, keep going
62, we're getting through
0-8-9-9, on time
8-6-2-8-0-3-4
There's only a few more!
8-2, then 5-3
42, 11, 7-0 and 67
We're done! Was that fun?
Learning random digits
So that you can brag to your friends
Step-by-step explanation:
Hi there!
PART A:
The system of equations we would use would be:
x + y = 22 (amount of items)
3x + 1y = 30 (cost)
Variables:
x = the amount of strawberry wafers bought at the price of $3
y = the amount of chocolate wafers bought at the price of $1
PART B:
To solve, we'll use substitution because we can easily isolate a variable using the first equation.
Work:
x + y = 22 (first equation)
y = 22 - x (isolating a variable)
3x + 1y = 30 (second equation)
3x + (22 - x) = 30 (substituting into the second equation)
2x + 22 = 30 (simplifying)
2x = 8 (subtracting)
x = 4 strawberry wafers
4 + y = 22 (substituting x into the first equation to solve for y)
y = 18 chocolate wafers
ANSWER:
They bought 4 strawberry wafers and 18 chocolate wafers.
Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
