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3 years ago

Pls Help ASAP if you. Can

Mathematics

1 answer:

n200080 [17]3 years ago

5 0

I think it’s b because it would make the most sense I believe but I’m really sorry if I’m wrong

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There are 390 sixth graders at Fairview Middle School. If 1/5 of the sixth graders have a pet fish and 2/3 have a pet dog, how m

denis23 [38]

I am thinking your answer is 78 students. You do 1/5 times 390. And I think the the part about the dog is just extra information.

7 0

3 years ago

Opal wanted to make some necklaces and sell them at a craft store. She made 37 necklaces and each necklace had somewhere between

alexandr402 [8]

<h3>The total number of beads used in making 37 necklaces is between 2,664 beads and 2,849 beads.</h3>

Step-by-step explanation:

Here, as given: The number of necklace made by Opal = 37

The least number of bead used in each necklace = 72

So, if each necklace is made using the least number of beads then,

The total number of beads used in 37 necklace = 37 x ( beads in 1 necklace)

= 37 x 72 = 2,664 beads

So, the least number of total beads used in 37 necklaces = 2,664 beads

The highest number of bead used in each necklace = 77

So, if each necklace is made using the highest number of beads then,

The total number of beads used in 37 necklace = 37 x ( beads in 1 necklace)

= 37 x 77 = 2,849 beads

So, if highest number of total beads used in 37 necklaces = 2,849 beads

Hence, the total number of beads used in making 37 necklaces is between 2,664 beads and 2,849 beads.

5 0

3 years ago

Hello today is my birthday please help !!

scoray [572]

Answer:

the last one(y=2(2/3)^x) is the correct answer

Step-by-step explanation:

I identify two coordinate on the graph (0,2) and (1,3) and I noticed only the last one gives you a appropriate output if you plug the correspond input value

4 0

2 years ago

If the distance covered by an object in time t is given by s(t)=t^2+5t , where s(t) is in meters and t is in seconds, what is th

alisha [4.7K]

Answer:

E. 44 meters

Step-by-step explanation:

The function that models the distance covered by the object is

$s(t)=t^2+5t$

where s(t) is in meters and t is in seconds.

The distance covered by the object after 1 second is

$s(1)=1^2+5(1)=6m$

The distance covered by the object after 1 second is

$s(1)=5^2+5(5)=50m$

The distance covered between 1 second and 5 seconds is

50-6=44m

6 0

3 years ago

How to find lengths from hypotenuse

Phoenix [80]

Can you elaborate on the question??

3 0

3 years ago

Read 2 more answers