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Sholpan [36]
3 years ago
6

The length of a rectangular garden ABCD is 9 feet more than its width. It is surrounded by a brick walkway 4 feet wide as shown

below. Suppose the total area of the walkway is 400 square feet. 25. What are the dimensions of the garden?
Mathematics
1 answer:
Anna71 [15]3 years ago
5 0

Answer:

  16.5 ft by 25.5 ft

Step-by-step explanation:

Let w represent the width of the garden in feet. Then w+9 is the garden's length, and w(w+9) represents its area.

The surrounding walkway adds 8 feet to each dimension, so the total area of the garden with the walkway is ...

  (w+8)(w+9+8) = w^2 +25w +136

If we subtract the area of the garden itself, then the remaining area is that of the walkway:

  (w^2 +25w +136) - (w(w+9)) = 400

  16w + 136 = 400 . . .simplify

  16w = 264 . . . . . . . . subtract 136

  264/16 = w = 16.5 . . . . . width of the garden in feet

  w+9 = 25.5 . . . . . . . . . . .length of the garden in feet

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The required ratio of cakes baked to hours worked = 30: 1

<u>Concept:</u>

We know that a ratio is a term in mathematics that signifies how many times one value contains the other.

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<u>Explanation:</u>

From the given graph, it can observe that,

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3 years ago
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Answer:

Option 2  50 ≤ s ≤ 100

Option 5 She could deposit $50

Option 6 She could deposit $75

Step-by-step explanation:

Let

s -----> amount of money Layla deposit into a saving account

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s\leq 0.50*200 -----> s\leq \$100

The compound inequality is

\$50 \leq s\leq \$100

<em>Verify each case</em>

case 1) 25 ≤ s ≤ 50

The statement is false

see the procedure

case 2) 50 ≤ s ≤ 100

<u>The statement is True</u>

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case 3) s ≤ 25 or s ≥ 50

The statement is false

Because is s ≤ 100 and  s ≥ 50

case 4) s ≤ 50 or s ≥ 100

The statement is false

Because is s ≤ 100 and  s ≥ 50

case 5) She could deposit $50

<u>The statement is true</u>

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case 6) She could deposit $75

<u>The statement is true</u>

Because the value of s satisfy the compound inequality  \$50 \leq s\leq \$100

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