Scientific notation is
where 1≤x<10 and b is an integer
b is how many spaces you had to move the decimal to the left in the original number to obtain x
so
48,100,000,000,000
to
4.8100000000000
the decimal was moved 13 spaces
so b=13
a=4.81
in scientific notation, 48,100,000,000,000 is
Answer:
5%
Step-by-step explanation:
Look at the values from high school athletes (the first row of numbers) to the values of college student athletes (the second row). Since we are only looking for male percentages, ignore the women's basketball
Take any of the college values, and divide it by the high school values. After this, multiply by 100 to get a percentage
Example, 56500 ÷ 983600 = 0.05
0.05 * 100 = 5%
You will get 5% for all males sports in this table
Answer:
Which of the following questions allows for variability?
How many students visited the nurse on Monday, September 15, 2014, at your school?
How many free throws can a person make in one minute?
How much money do doctors earn per year?
How tall are the players on the Harlem Globetrotters?
Step-by-step explanation:
HELP IM SRRY
Answer:
Step-by-step explanation:
The function that represents the amount of caffeine, in milligrams, remaining in a body after drinking two mountain dew sodas is given by f(t) = 110(0.8855)^t, where t is time in hours.
Answer:
0.284
Step-by-step explanation:
To carry out this calculation, we begin by describing the sampling distribution of the sample proportion.
The sample size is n = 50 and the population proportion of teachers who made an apparel purchase is 0.56.
Shape: Because np = (50)(0.56) = 28 and n(1 – p) = (50)(0.44) = 22 are both at least 10, the shape of the sampling distribution of the sample proportion is approximately Normal.
Center:
μ
p
^
=
p
=
0
.
5
6
μ
p
^
=p=0.56
Variability: The standard deviation of the sample proportion is approximately
(
0
.
5
6
)
(
0
.
4
4
)
5
0
≈
0
.
0
7
0
2
50
(0.56)(0.44)
≈0.0702.
P(
p
^
p
^
> 0.6) = Normalcdf(lower: 0.6, upper: 1000, mean: 0.56, SD: 0.0702) = 0.284.
P
(
p
^
>
0
.
6
)
=
P
(
z
>
0
.
6
−
0
.
5
6
0
.
0
7
0
2
)
=
P
(
z
>
0
.
5
7
)
=
1
−
0
.
7
1
5
7
=
0
.
2
8
4
3
P(
p
^
>0.6)=P(z>
0.0702
0.6−0.56
)=P(z>0.57)=1−0.7157=0.2843
