The number of days when the season pass would be less expensive than the daily pass is 5 days.
<h3>How many days would the season pass be less expensive?</h3>
The equation that represents the total cost of skiing with the daily pass : (daily pass x number of days) + (cost of renting skis x number of days)
$70d + $20d = $90d
The equation that represents the total cost of skiing with the seasonal pass : cost of season pass + (cost of renting skis x number of days)
$300 + $20d
When the season pass becomes less expensive, the inequality equation is:
Daily pass > season pass
$90d > $300 + $20d
In order to determine the value of d, take the following steps:
Combine and add similar terms: $90d - $20d > $300
70d > $300
Divide both sides by 70 d > $300 / 70
d > 4.3 days
Approximately 5 days.
To learn more about how to calculate inequality, please check: brainly.com/question/13306871
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Answer:
5 row, 3 left
Step-by-step explanation:
She has 48 flowers, 5 flowers one row
How many rows can she make? So divide
48/ 5
= 9.6
So she can only make 9 rows
The leftovers flowers are the flowers that didn't manage to make 5 per row
Therefore, if she can make 9 rows, in other words 9 x 5 = 45
45 flowers were able to be placed in a sequence of 5 per row
So the ones that are left is
48 - 45
= 3
Answer:
y - 8 = (3/2)(x + 4)
Step-by-step explanation:
As we move from (-4, 8) to (2, -1), x increases by 6 (this is the run) and y decreases by 9 (this is the "rise"). Thus, the slope is
m = rise / run = 9/6, or 3/2.
Using the point-slope form of the equation of a straight line, we get:
y - 8 = (3/2)(x + 4)
